Solve the remaining please An electron is moving horizontally to the right with speed 4 × 106 m/s. What is the magnetic field due to this moving electron at the indicated locations in the figure? Each location is d = 5 cm from the electron, and the angle 0 = 33°. Give both magnitude and direction of the magnetic field at each location.P1d-P2P5P3P4X Tinto the pageP1 = 4.56e-18P2 =T no magnetic fieldT out of the pageP3 =P4T out of the pageP5 =T no magnetic field vP6 =T into the page

Answered: Image /qna-images/answer/bd7c6517-0e0d-49e0-8a39-478e4daef9e0.jpg

An electron is moving horizontally to the right with speed 4 x 106 m/s. What is the magnetic field due to this moving electron at the indicated locations in the figure? Each location is d = 5 cm from the electron, and the angle e = 33°. Give both magnitude and direction of the magnetic field at each location. P- 4.560-18 x Tinto the page P2 = no magnetic field v P3 - T out of the page v T out of the page Ps - T no magnetic field v T into the page

An electron is moving horizontally to the right with speed 4 x 106 m/s. What is the magnetic field due to this moving electron at the indicated locations in the figure? Each location is d = 5 cm from the electron, and the angle e = 33°. Give both magnitude and direction of the magnetic field at each location. P- 4.560-18 x Tinto the page P2 = no magnetic field v P3 - T out of the page v T out of the page Ps - T no magnetic field v T into the page

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter19: Magnetism

Section: Chapter Questions

Problem 44P: A long, straight wire going through the origin is carrying a current of 3.00 A in the positive...

See similar textbooks

Similar questions

Why is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46
Two long, straight, parallel wires carry currents that are directed perpendicular to the page as shown in Figure P30.9. Wire 1 carries a current I1, into the page (in the negative z direction) and passes through the x axis at x = +. Wire 2 passes through the x axis at x = 2a and carries an unknown current I2. The total magnetic field at the origin due to the current-carrying wires has the magnitude 20I1(2a). The current I2 can have either of two possible values, (a) Find the value of with the smaller magnitude, stating it in terms of I1, and giving its direction. (b) Find the other possible value of I2.
A long, straight wire going through the origin is carrying a current of 3.00 A in the positive z-direction (Fig. P19.44). At a point a distance r = 1.20 m from the origin on the positive x-axis, find the (a) magnitude and (b) direction of the magnetic field. At a point the same distance from the origin on the negative y-axis, find the (c) magnitude and (d) direction of the magnetic field. Figure P19.44
A strong magnet is placed under a horizontal conducting ring of radius r that carries current I as shown in Figure P28.27. If the magnetic field B makes an angle with the vertical at the rings location, what are (a) the magnitude and (b) the direction of the resultant magnetic force on the ring? Figure P28.27
One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280 m, z = 0). (a) Where in the plane of the two wires is the total magnetic field equal to zero? (b) A particle with a charge of 2.00 C is moving with a velocity of 150iMm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) What If? A uniform electric field is applied to allow this particle to pass through this region undetected. Calculate the required vector electric field.
Determine the initial direction of the deflection of charged particles as they enter the magnetic fields shown in Figure P29.2.
An alpha-particle ( m=6.641027kg , q=3.21019C ) travels in a circular path of radius 25 cm in a uniform magnetic field of magnitude 1.5 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?
A horizontal power line oflength 58.0 in carries a current of 2.20 kA northward as shown in Figure P29.41. The Earths magnetic field at this location has a magnitude of 5.00 10-5 T. The field at this location is directed toward the north at an angle 65.0 below the power line. Find (a) the magnitude and (b) the direction of the magnetic force on the power line.