An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 2.0 cm, and the electric field within the capacitor has a magnitude of 2.4 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? KE positive i Electric field Electron

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Chapter26: Capacitance And Dielectrics
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Problem 26.8P
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An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the
drawing). The plates are separated by a distance of 2.0 cm, and the electric field within the capacitor has a magnitude of 2.4 x 106 V/m.
What is the kinetic energy of the electron just as it reaches the positive plate?
KE positive =
i
-Electric field
Electron
F
Transcribed Image Text:An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 2.0 cm, and the electric field within the capacitor has a magnitude of 2.4 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? KE positive = i -Electric field Electron F
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