An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 249 m/s2   What is the magnitude of the electric field?

University Physics Volume 2
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ISBN:9781938168161
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Chapter5: Electric Charges And Fields
Section: Chapter Questions
Problem 92P: An electron and a proton, each starting from rest, are accelerated by the same uniform electric...
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An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 249 m/s2

 

What is the magnitude of the electric field?

Expert Solution
Step 1

Given,

Acceleration of the electron(a) = 249 m/s2

Force balance on electron

Fn = Fe

m*a = q*E

E = m*a/q

m = mass of electron = 9.109×1031 kg

q = charge on electron = 1.60 × 1019 C

a = acceleration = 249 m/s2

So using above values:

E = (9.1 * 10-31*249)/(1.6*10-19)

E = 1.41*10-9 N/C

 

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