An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 249 m/s2 What is the magnitude of the electric field?
An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 249 m/s2 What is the magnitude of the electric field?
Chapter5: Electric Charges And Fields
Section: Chapter Questions
Problem 92P: An electron and a proton, each starting from rest, are accelerated by the same uniform electric...
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An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 249 m/s2
What is the magnitude of the electric field?
Expert Solution
Step 1
Given,
Acceleration of the electron(a) = 249 m/s2
Force balance on electron
Fn = Fe
m*a = q*E
E = m*a/q
m = mass of electron = 9.109×10−31 kg
q = charge on electron = 1.60 × 10−19 C
a = acceleration = 249 m/s2
So using above values:
E = (9.1 * 10-31*249)/(1.6*10-19)
E = 1.41*10-9 N/C
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