An electron, m = 9.109 × 10-31kg, at point A has a speed v, of 1.96 × 10®m/s. Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B. vo В A -10.0 cm. O 2.2e-5 T O 2.2e-4 T O 1.1e-4 T О 1.1е-6 T

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Chapter24: Magnetic Fields
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An electron, m, = 9.109 x 1031kg, at point A has a speed v, of 1.96 x 10°m/s. Find the magnitude of the magnetic field that will cause the electron to follow the
semicircular path from A to B.
A
В
10.0 cm
2.2e-5 T
O 2,2e-4 T
1.1e-4 T
O 1.1e-6 T
O o o O
Transcribed Image Text:An electron, m, = 9.109 x 1031kg, at point A has a speed v, of 1.96 x 10°m/s. Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B. A В 10.0 cm 2.2e-5 T O 2,2e-4 T 1.1e-4 T O 1.1e-6 T O o o O
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