An electron ( me = 9.11\( \times \)10- kg q=1.6\( \times \)10-91 C) moves in a circular path perpendicular to a %3D 31 uniform magnetic field with a magnitude of 9 mT. If the speed of the electron is 1.50 \( \times \)107 m/s, determine the radius of the circular path ( in units of cm).

Glencoe Physics: Principles and Problems, Student Edition
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Author:Paul W. Zitzewitz
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Chapter26: Electromagnetism
Section: Chapter Questions
Problem 42A
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An electron ( me = 9.11\( \times \)10"
31 kg q=1.6\( \times \)10*91 C) moves
in a circular path perpendicular to a
uniform magnetic field with a
magnitude of 9 mT. If the speed of the
electron is 1.50 \( \times \)107 m/s,
determine the radius of the circular
path ( in units of cm).
Select one:
A. 0.03
B. 1.17
C. 0.95
D. 0.50
E. 1.39
Transcribed Image Text:An electron ( me = 9.11\( \times \)10" 31 kg q=1.6\( \times \)10*91 C) moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 9 mT. If the speed of the electron is 1.50 \( \times \)107 m/s, determine the radius of the circular path ( in units of cm). Select one: A. 0.03 B. 1.17 C. 0.95 D. 0.50 E. 1.39
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