Question

Asked Aug 1, 2019

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An electron moves through a uniform magnetic field given by B vector*= B _{x i}+*(4.26

Step 1

**Given**

The magnetic field *B = B*_{x }*i + (*4.26* B*_{x}*) **j*

The velocity of the electron* v =* (2.12* i + *4.91* j*)* m/s*

The force acting on the electron *F =* (7.80* *x 10^{-19}* k* )* N*

**Known**

The magnitude of the charge of electron q = e = 1.6 x 10^{-19} C

Step 2

**Understanding**

The electron moves in the xy plane

The magnetic field is acting in the xy plane

The force is acting in the positive z axis direction

**Formula Used**

When a charges particle is moving in a magnetic field, the charged particle will experience a force in the direction perpendicular to both the velocity and the magnetic field. This force is called magnetic Lorentz force

Step 3

**Solution**

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