An electron (q = 1.6×10^−19C) is moving to the right with velocity v = 5m/s under the influence of a constant magnetic field of strength B = 10T. The magnetic field makes an angle of 45 deg. with the electron’s trajectory. What is the force (magnitude and direction) on this electron? sin 45 = √2/2 .

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter22: Magnetic Forces And Magnetic Fields
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An electron (q = 1.6×10^−19C) is moving to the right with velocity v = 5m/s under the influence of a constant magnetic field of strength B = 10T. The magnetic field makes an angle of 45 deg. with the electron’s trajectory. What is the force (magnitude and direction) on this electron? sin 45 = √2/2 .

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