An electron with a horizontal speed of 2300000 m/s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 160 N/C. The plates are 3 cm long. Calculate the angle to the horizontal, 0 (in degrees), that the electron would pass through the plates with. e ++++++ TITI 11 11 11 || OII 0 y 2. X

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.56P: Two horizontal metal plates, each 10.0 cm square, are aligned 1.00 cm apart with one above the...
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An electron with a horizontal speed of 2300000 m/s and no vertical component of
velocity passes through two horizontal parallel plates, as shown. The magnitude of the
electric field between the plates is 160 N/C. The plates are 3 cm long. Calculate the
angle to the horizontal, 0 (in degrees), that the electron would pass through the plates
with.
e-
+ + + + + +
II
||
||
0
||
y
X
Transcribed Image Text:An electron with a horizontal speed of 2300000 m/s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 160 N/C. The plates are 3 cm long. Calculate the angle to the horizontal, 0 (in degrees), that the electron would pass through the plates with. e- + + + + + + II || || 0 || y X
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