An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.54 cm and a plate area of A = 25.0 cm?. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before pC after Q, = pC (b) Determine the capacitance (in F) and potential difference (in V) after immersion. C, = AV, = (c) Determine the change in energy (in nJ) of the capacitor. AU = n)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter26: Capacitance And Dielectrics
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Problem 26.12OQ: (i) Rank the following five capacitors from greatest to smallest capacitance, noting any cases of...
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An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.54 cm and a
plate area of A = 25.0 cm2. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0.
%3D
(a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before
pC
%3D
after
pC
%3D
(b) Determine the capacitance (in F) and potential difference (in V) after immersion.
F
%3D
AVF
V.
%3D
(c) Determine the change in energy (in nJ) of the capacitor.
AU =
nJ
(d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference.
Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before
Q, =
pC
after
Qr
pC
Determine the capacitance (in F) and potential difference (in V) after immersion.
AV
%3D
Determine the change in energy (in nJ) of the capacitor.
AU =
nJ
Transcribed Image Text:An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.54 cm and a plate area of A = 25.0 cm2. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. %3D (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before pC %3D after pC %3D (b) Determine the capacitance (in F) and potential difference (in V) after immersion. F %3D AVF V. %3D (c) Determine the change in energy (in nJ) of the capacitor. AU = nJ (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q, = pC after Qr pC Determine the capacitance (in F) and potential difference (in V) after immersion. AV %3D Determine the change in energy (in nJ) of the capacitor. AU = nJ
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