Answered: An FM radio broadcast used a modulator…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Concept explainers

Question

An FM radio broadcast used a modulator with a frequency deviation sensitivity of 5KHz/V, a 2Vp – 10 kHz modulating signal, and a 10Vp – 88MHz carrier Signal , determine :

(a) Actual minimum bandwidth from the Bessel function table in kHz

(b) Appropriate minimum bandwidth using Carson’s rule in kHz

(d) The FM modulated waveform carrier and significant sideband components amplitudes; NOTE: Use this format in providing your answers to this problem: VJ0=x.xx v,VJ1=x.xx v,VJn=x.xx v; where VJO is the modulated carrier amplitude, VJ1-VJn is the amplitudes in significant sideband components and the number of sidebands (n) depending on your computation.

(e) The unmodulated carrier power (W) for the FM modulator assumes that the load resistance is 50 Ω

f) The corresponding FM modulated waveform carrier and significant sideband components power and its total power in mW. Note: Use this format in providing your answers to this problem: PJ0=xxx.xx mW,PJ1=xxx.xx mW,PJ2=xxx.xx mW,PJn=xxx.xx mW,PT=xxx.xx mW; where PJO is the carrier power, PJ1-PJn is the power in significant sideband and PT is the total power and the number of sidebands (n) depending on your computation.

Bessel Function Table
Modulating
Index
Sideband Frequency Pair
Carrier
JO
J1
J2
J3
J4
J5
J6
J7
0.00
1.00
0.25
0.98
0.50
0.94
1.00
0.77
0.44
0.11
0.02
1.50
0.51
0.56
0.23
0.06
0.01
2.00
0.22
0.58
0.35
0.13
0.03
2.40
0.00
0.52
043
0.20
0.06
0.02
2.50
-0.05
0.50
0.45
0.22
0.07
0.02
0.01
3.00
-0.26
0.34
0.49
0.31
0.13
0.04
0.01

Here n is not given , sO Take n=1
a) ACCording to Besel fynction, the
table
minimum Bandwid th, B = 2nFm
where n= number of side bamds.
Folne)
>lB= 20 KHZ
B= 2 fm = 2X1OK
(08)FOX n= 7 ,B= 14 Fm > B= 140KHZ
b) carson's rule,
According to
B =
2( Af + fin)
where
3.
Af = KF Am = 5 XI0 x 2 = 1OKHZ
: B= 2/ 10K+ 1OK)
>B= 40 KH2
c) / u=
Afactual
x/00%.
Afman
> / u =
JOKHZ
75 KH Z
X100.).
> /1 u = 13.3 3-/

Expert Solution

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions