Question
Asked Dec 25, 2019
2 views

An inductor and a resistor are connected in series. When
connected to a 60. - Hz, 90. - V (rms) source, the voltage drop
across the resistor is found to be 50. V (rms) and the power
delivered to the circuit is 14 W. Find (a) the value of the
resistance and (b) the value of the inductance.

check_circle

Expert Answer

Step 1

part A :

 

help_outline

Image Transcriptionclose

Given info: An inductor and a resistor are connected in series. The frequency of the source is 60 Hz. The rms voltage of the source is 90 V. The rms voltage drop across the resistor is 50 V. The power delivered to the circuit is 14W. The average power delivered to a resistor is given by, Pa = ImsR Ris the resistance Irms is the rms current flowing in the circuit The rms voltage drop across the resistor is given by, AVrms,R = IrmsR

fullscreen
Step 2
help_outline

Image Transcriptionclose

The expression of rms current in terms of rms voltage drop across the resistor will be, AVms,R TRS Irms Substitute the expression for rms current in the expression of average power and rearrange, AVms,R Pa = ( R (AVrms,R)² %3D Rewrite the above expression for the resistance, (AVms,r) R= Pa

fullscreen
Step 3
help_outline

Image Transcriptionclose

Substitute 50 V for AVms R and 14 W for Pa to determine the resistance of the circuit, (50 V)? R = 14 W = 1.8 × 10² N Conclusion: The resistance of the circuit is 1.8 × 10² N.

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Physics

Other

Related Physics Q&A

Find answers to questions asked by student like you
Show more Q&A
add