An insurance actuary claims that the mean footwell intrusions for small and midsize cars are equal. Crash tests at 40 mph were performed on 18 randomly selected small cars and 8 randomly selected midsize cars. The amount that the footwell intruded on the driver's legs was measured. The mean footwell intrusion for the small cars was 11.5 centimeters with a standard deviation of 4.29 centimeters. The mean footwell intrusion for the midsize cars was 11.1 centimeters with a standard deviation of 3.71 centimeters. At a= 0.20, answer parts (a) through (e). Assume the population variances are equal. If convenient, use technology to solve the problem.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 7PPS
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1. Find the critical​ value(s) and identify the rejection​ region(s).

An insurance actuary claims that the mean footwell intrusions for small and midsize cars are equal. Crash tests
at 40 mph were performed on 18 randomly selected small cars and 8 randomly selected midsize cars. The
amount that the footwell intruded on the driver's legs was measured. The mean footwell intrusion for the small
cars was 11.5 centimeters with a standard deviation of 4.29 centimeters. The mean footwell intrusion for the
midsize cars was 11.1 centimeters with a standard deviation of 3.71 centimeters. At a= 0.20, answer parts (a)
through (e). Assume the population variances are equal. If convenient, use technology to solve the problem.
Transcribed Image Text:An insurance actuary claims that the mean footwell intrusions for small and midsize cars are equal. Crash tests at 40 mph were performed on 18 randomly selected small cars and 8 randomly selected midsize cars. The amount that the footwell intruded on the driver's legs was measured. The mean footwell intrusion for the small cars was 11.5 centimeters with a standard deviation of 4.29 centimeters. The mean footwell intrusion for the midsize cars was 11.1 centimeters with a standard deviation of 3.71 centimeters. At a= 0.20, answer parts (a) through (e). Assume the population variances are equal. If convenient, use technology to solve the problem.
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