An object is moving with velocity (in ft/sec) v(t) = t² - 2t + 2. At t = 0, the object has a position of 8 = 6 feet. Use antiderivatives to find the position equation. s(t) = The position of the object at 6 seconds is feet.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.6: Proportion And Variation
Problem 22E: Find the constant of proportionality. z is directly proportional to the sum of x and y. If x=2 and...
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Question 16: An object is moving with velocity (in ft/sec) v(t)=t2−2t+2 t=0, the object has a position of s=6 feet.



Use antiderivatives to find the position equation.
s(t)=  __________

The position of the object at 6 seconds is __________ feet.

An object is moving with velocity (in ft/sec) v(t) = t² - 2t + 2.
At t = 0, the object has a position of s = 6 feet.
Use antiderivatives to find the position equation.
s(t)
The position of the object at 6 seconds is
feet.
Transcribed Image Text:An object is moving with velocity (in ft/sec) v(t) = t² - 2t + 2. At t = 0, the object has a position of s = 6 feet. Use antiderivatives to find the position equation. s(t) The position of the object at 6 seconds is feet.
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