\ (#655261){Two Lens System}An object is placed 22.3 cm to the left of a positive lens of focal length +45.9 cm. A second positive lens, of focal length+67.8 cm is placed to the right of the first lens with a separation of 86.8 cm.Calculate the position of the final image relative to the second lens. (Report a positive number if the image is to the rightof the second lens, and a negative number if it is to the left of the second lens. Assume both lenses are thin sphericallenses).Do this calculation in stages:1) Find the position of the image formed by the first lens.2) Use that image (at whatever location it is) as an object for the second lens, and find the image formed by the secondlens.Image size: s ML MaxFigure is not drawn to scalePlease enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8Enter answer here124cm124 cm XYourAnswer

Given an object is at a distance u=22.3 cm to the left of a lens having focal length f=+45.9 cm Thus…

An object is placed 22.3 cm to the left of a positive lens of focal length +45.9 cm. A second positive lens, of focal length +67.8 cm is placed to the right of the first lens with a separation of 86.8 cm. Calculate the position of the final image relative to the second lens. (Report a positive number if the image is to the right of the second lens, and a negative number if it is to the left of the second lens. Assume both lenses are thin spherical lenses).

An object is placed 22.3 cm to the left of a positive lens of focal length +45.9 cm. A second positive lens, of focal length +67.8 cm is placed to the right of the first lens with a separation of 86.8 cm. Calculate the position of the final image relative to the second lens. (Report a positive number if the image is to the right of the second lens, and a negative number if it is to the left of the second lens. Assume both lenses are thin spherical lenses).