An object is thrown upward at a speed of 141 feet per second by a machine from a height of 15 feet off the ground. The height of the object after tt seconds can be found using the equation s(t)=−16t2+v0t+s0s(t)=-16t2+v0t+s0, where v0v0 is the initial velocity and s0s0 is the initial height.  Give all numerical answers to 2 decimal places. (a) When will the object reach its maximum height?  _____seconds. (b) What is its maximum height?  _____feet. (c) When will the object reach the ground?  _____seconds.

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