An object moves along the x-axis with its position x given as a function of time t by x (t) = Ct² – Dt + B %3D What is the object's velocity v as a function of time? v (t) =
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- The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.A particle moves along the x axis. Its position is given by the equation x = 2 + 3t 4t2, with x in meters and t in seconds. Determine (a) its position when it changes direction and (b) its velocity when it returns to the position it had at t = 0.At time t=0s, an object is moving to the right with a velocity v that can be modeled by the equation v=(4.2 m/s)-(1.4 m/s2)t. At what time, if any, does the object change its direction of motion?
- A particle is moving horizontally with constant acceleration. The position (x, in meters) as a function of time (t, in seconds) is given by x= 0.798 t^2 + 0.3552 t + 0.0355. Based on this information, the acceleration of the particle is what?A particle moves along the x axis according to the equation x=2.00 + 3.00t - 1.00t², where x is in meters and t is in seconds. At t=3.00s, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.A particle moves along the positive x-axis and its position as a function of time is x(t)=(19.9 m/s)t − (1.7 m/s^2)t^2. What is the average velocity in the time interval between 2.3s and 3.7s in m/s?
- The following equations give the position x(t) of a particle in four situations (in each equation, x is in meters, tis in seconds, and t> 0): (1) x = 3t - 4: (2) x = -5t3 + 4t2 + 6: (3) x = 2/t2 - 4/t; (4) x = 5t2 3. (a) In which situation is the acceleration a of the particle constant?The velocity of an object is given by the expression v(t) = 3.00 m/s + (3.00 m/s3)t 2, where t is in seconds. Determine the position of the object as a function of time if it is located at x = 1.00 m at time t = 0.000 s.A particle moves along the x-axis according to the equation x = 2.00 +3.00t -1.00t^2, where x is in meters and t is in seconds. At t = 3.00s , find the acceleration of the particle.
- the velocity of an object is given by the expression v (t) = 3.00m / s + (2.00 m / s ^ 3) t ^ 2. determine the position of the object as a function of time without being located at x = 1.00m at time t = 0.00sA spaceship is traveling at a constant velocity of v(t) = 300.0i m/s when its rockets fire, giving it an acceleration of a(t) = (9.0i + 9.0k) m/s^2. What is its velocity (in m/s) 4 s after the rockets fire? (Express your answer in vector form.)An object's position in the x-direction as a function of time is given by the expression; x(t) = 5t2 + 2t where are quantities have proper SI Units. What is the object's average velocity in the x-direction between the times t = 1.3 s and t = 2.28 s.