An object of mass 0.50 kg is released from the top of a building of height 2 m. The object experiences a horizontal constant force of 1.4 N due to the wind blowing. (a) Find the time (in s) it takes for the object to strike the ground. (b) What is the magnitude of the acceleration of the object (in m/s2)? m/s2 (c) Through what horizontal distance does the object move (in m) before it hits the ground? m
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- If a single constant force acts on an object that moves on a straight line, the objects velocity is a linear function of time. The equation v = vi + at gives its velocity v as a function of time, where a is its constant acceleration. What if velocity is instead a linear function of position? Assume that as a particular object moves through a resistive medium, its speed decreases as described by the equation v = vi kx, where k is a constant coefficient and x is the position of the object. Find the law describing the total force acting on this object.a slab of mass m1 40 kg rests on a frictionless floor, and a block of mass m2 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40.A horizontal force of magnitude 100 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?An object of mass 0.50 kg is released from the top of a building of height 9 m. The object experiences a horizontal constant force of 2.1 N due to the wind blowing. a) Find the time (in s) it takes for the object to strike the ground. b) What is the magnitude of the acceleration of the object (in m/s^2). c) Through what horizontal distance does the object move (in m) before it hits the ground?
- A spaceship lifts off vertically from the Moon, where g = 1.6 m/s2. If the ship has an upward acceleration of 1.0 m/s2 as it lifts off, what is the magnitude of the force exerted by the ship on its pilot, who weighs 735 N on Earth?In the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?The following forces are acting on a 250 g box on a horizontal surface: A downward force of gravity with magnitude 2.45 N. An upward normal force with magnitude 2.45 N. A rightward pull from a rope of 5.0 N. A leftward kinetic friction force with magnitude 7.5 N. At this instant, what is the magnitude of the acceleration of the box?
- A block with mass m1 = 9.2 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μk = 0.58. A second block with a mass m2 = 10.8 kg is connected to the first by an ideal string passing over an ideal pulley such that the second block is suspended vertically. The second block is released from rest, and motion occurs. Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, ΣFy, for block 2. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction, ΣFx for block 1. Block 1 accelerates along the tabletop, in the horizontal direction, while block 2 moves vertically. With the coordinate system provided in the drawing, we may write a⃗ 1=a1i^a→1=a1i^ and a⃗ 2=a2y^a→2=a2y^. Write an expression that relates the vertical component of the acceleration of block 2 to the horizontal component of the acceleration of block 1. Write an expression using the…A block with mass m1 = 9.2 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μk = 0.58. A second block with a mass m2 = 10.8 kg is connected to the first by an ideal string passing over an ideal pulley such that the second block is suspended vertically. The second block is released from rest, and motion occurs. Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, ΣFy, for block 2. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction, ΣFx for block 1. Block 1 accelerates along the tabletop, in the horizontal direction, while block 2 moves vertically. With the coordinate system provided in the drawing, we may write a⃗ 1=a1i^a→1=a1i^ and a⃗ 2=a2y^a→2=a2y^. Write an expression that relates the vertical component of the acceleration of block 2 to the horizontal component of the acceleration of block 1. Write an expression using the…A block of mass m1 = 3.70 kg on a frictionless plane inclined at angle is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.30 kg. What are (a) the magnitude of the acceleration of each block (b) the direction of the acceleration of the hanging block, and (c) the tension in the cord?
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