An overly involved "neighborhood watch" group has been investigating the length of lawns. In years past, lawns had been mowed to a mean length of 3.3 inches. A recent random sample of lawn lengths is given below. Conduct an appropriate test, at a 5% significance level, to determine if the overall mean lawn length is now higher than 3.3 inches. Data (lawn lengths, measured in inches): 2.00 4.51 3.60 4.47 3.52 2.84 3.42 2.99 3.94 2.99 4.55 3.67 4.45 3.24 3.39 5.10 3.65 Q1 sample mean (rounded to 3 decimal places proeprly): ¯x=x¯= Q2) Standard deviation of the sample (rounded to 3 decimal places proeprly): s= Q3)test statistic (rounded to 4 decimal places proeprly): t= Q4)P-value (rounded to 4 decimal places proeprly):
An overly involved "neighborhood watch" group has been investigating the length of lawns. In years past, lawns had been mowed to a mean length of 3.3 inches. A recent random sample of lawn lengths is given below. Conduct an appropriate test, at a 5% significance level, to determine if the overall mean lawn length is now higher than 3.3 inches. Data (lawn lengths, measured in inches): 2.00 4.51 3.60 4.47 3.52 2.84 3.42 2.99 3.94 2.99 4.55 3.67 4.45 3.24 3.39 5.10 3.65 Q1 sample mean (rounded to 3 decimal places proeprly): ¯x=x¯= Q2) Standard deviation of the sample (rounded to 3 decimal places proeprly): s= Q3)test statistic (rounded to 4 decimal places proeprly): t= Q4)P-value (rounded to 4 decimal places proeprly):
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter11: Data Analysis And Displays
Section11.3: Shapes Of Distributions
Problem 20E
Related questions
Question
Testing a claim about a population mean: t-Test
An overly involved "neighborhood watch" group has been investigating the length of lawns. In years past, lawns had been mowed to a mean length of 3.3 inches.
A recent random sample of lawn lengths is given below. Conduct an appropriate test, at a 5% significance level, to determine if the overall mean lawn length is now higher than 3.3 inches.
Data (lawn lengths, measured in inches):
| 2.00 | 4.51 | 3.60 | 4.47 | 3.52 | 2.84 | 3.42 | 2.99 |
| 3.94 | 2.99 | 4.55 | 3.67 | 4.45 | 3.24 | 3.39 | 5.10 |
| 3.65 |
Q1
sample mean (rounded to 3 decimal places proeprly): ¯x=x¯=
Q2) Standard deviation of the sample (rounded to 3 decimal places proeprly): s=
Q3)test statistic (rounded to 4 decimal places proeprly): t=
Q4)P-value (rounded to 4 decimal places proeprly):
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 5 steps with 4 images
Recommended textbooks for you
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Algebra
ISBN:
9781680331141
Author:
HOUGHTON MIFFLIN HARCOURT
Publisher:
Houghton Mifflin Harcourt
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Algebra
ISBN:
9781680331141
Author:
HOUGHTON MIFFLIN HARCOURT
Publisher:
Houghton Mifflin Harcourt