An R-C series circuit consists of a capacitor with capacitance, C, connected in series with a resistor with resistance, R. The resistance, R, is a circuit parameter that opposes the amount of electric charges Q, passing through the circuit per unit time and causes a drop in potential given by Ohm's Law while the capacitance, C, is a circuit parameter that measures the amount of electric charges that the current carries and stores in the capacitor. Both the resistor and capacitor cause the total drop in electric potential and is equivalent to the total electromotive force, E, which is produced by a voltage source such as batteries.

University Physics Volume 2
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Chapter9: Current And Resistance
Section: Chapter Questions
Problem 84CP: In this chapter, most examples and problems involved direct current (DC). DC circuits have the...
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VR
R
E
An R-C series circuit consists of a capacitor with capacitance, C, connected in series with a resistor with
resistance, R. The resistance, R, is a circuit parameter that opposes the amount of electric charges Q, passing
through the circuit per unit time and causes a drop in potential given by Ohm's Law while the capacitance, C, is
a circuit parameter that measures the amount of electric charges that the current carries and stores in the
capacitor. Both the resistor and capacitor cause the total drop in electric potential and is equivalent to the total
electromotive force, E, which is produced by a voltage source such as batteries.
dQ
E =+R-
C
dt
As soon as the switch is opened, the initial charge Q, that is stored in the capacitor varies through time, t. In
the given differential equation above, the charge Q and the time t are the dependent and independent
variables, respectively. The electromotive force E, the resistance R, and the capacitance C are constants.
Using A as the constant of integration, find the general solution in explicit form Q = f(t). Knowing that there
are no electric charges stored in the capacitor yet before the switch is closed (at t = 0, Q = 0), set up the
particular solution of the given differential equation above in explicit form.
Transcribed Image Text:VR R E An R-C series circuit consists of a capacitor with capacitance, C, connected in series with a resistor with resistance, R. The resistance, R, is a circuit parameter that opposes the amount of electric charges Q, passing through the circuit per unit time and causes a drop in potential given by Ohm's Law while the capacitance, C, is a circuit parameter that measures the amount of electric charges that the current carries and stores in the capacitor. Both the resistor and capacitor cause the total drop in electric potential and is equivalent to the total electromotive force, E, which is produced by a voltage source such as batteries. dQ E =+R- C dt As soon as the switch is opened, the initial charge Q, that is stored in the capacitor varies through time, t. In the given differential equation above, the charge Q and the time t are the dependent and independent variables, respectively. The electromotive force E, the resistance R, and the capacitance C are constants. Using A as the constant of integration, find the general solution in explicit form Q = f(t). Knowing that there are no electric charges stored in the capacitor yet before the switch is closed (at t = 0, Q = 0), set up the particular solution of the given differential equation above in explicit form.
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