and a "0" to be false. P 1 1 1 1 0 0 0 0 q 1 1 0 0 1 1 0 Write a truth table for the proposition: (q^r)v(pr). Consider a "1" to be true 0 r 1 0 1 0 1 0 1 0 q^r (q^r) p r p➜¬r (q^r)v(pr)

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