and alem consists of amounts from city # 2. OA. Ho: H₁ H₂ Hy: Hy > H₂ OC. Ho: 1₁ = ₂ H₁: Hy H₂ hypothese $? Assume that population 1 consists of amounts from city OB. Ho: ₁5₂ H₁: 144₂ OD. Ho: H₁ #1₂ H₁: H₁ H₂ levels and popu

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Chapter1: Combinatorial Analysis
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Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of
baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected
from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05 significance
level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2
residents.
Click the icon to view the data table of strontium-90 amounts.
What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2
consists of amounts from city #2.
OA. Ho: H₁ H₂
H₁: H₁ H₂
о с. Но: 141=12
H₁: H₁ H₂
More Info
City #1
108
86
121
112
101
104
213
149
290
100
290
145
Print
City #2
117
83
100
85
81
107
110
111
149
133
101
209
Done
OB. Ho: H₁ H₂
H₁: H₁ H₂
OD. Ho: ₁₂
H₁: H₁ H₂
63
- X
Transcribed Image Text:Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. OA. Ho: H₁ H₂ H₁: H₁ H₂ о с. Но: 141=12 H₁: H₁ H₂ More Info City #1 108 86 121 112 101 104 213 149 290 100 290 145 Print City #2 117 83 100 85 81 107 110 111 149 133 101 209 Done OB. Ho: H₁ H₂ H₁: H₁ H₂ OD. Ho: ₁₂ H₁: H₁ H₂ 63 - X
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