Answer the following using Jacobi Method. Show complete solutions.2.) 9x1 - 13x2 + 4x3 = 111 4x1 + 22x2 -13x3 = -128 8x1 + 8x2 + 17x3 = 10This is the example/guide that might help. Step 3. Perform iterction until the values afSystem of Linear Equations (Iterative Methads)Iterative methads ave based on successiveimprovement of initial quesser for the sdlutionITERATIVE METHUDI : JACORI METHODStep 1. Rewrite the systemStep 2. Initializea value for the unknounsof zeru.tep 3. Perform iterction until the values althe unknawn dan't divevge anymore.falutExample:A 3xty-Z =32×+4y+zニフSolution:そtん-e = メY=7-2x-Z4Z:4-xtyスキメーh: x:0; y=0,2=0Ist ItercitionX,こ3-0+O3Y.= 7-2(0) - (0?=1.75Z,?4-04 O42ND ITERAION:メ2ラーy,ナ21-3-175+l>0.7533Y2:1-2x,*2フー2-D.1そz: 4-Xty、 4-1t154-1+1.75=1.1875 Sheuld oo be less than 0.005,5 decimdl3RD ITERATION:メッ=3- y2t2,%3D3-1+1.1875=1.0625%3DYo:フ-2x, -Z27-210.75)-1-1875こ1.0781252,- 4-メetyz 4 - C0-75) +|%3Di,06254'Iteration11.752.0-75|-187531.04251.078125U -994792 0.953125 1.0039061062541.0169271-001628 0-9895830-995985 0.994141 0.9901750.0995371-0006761.00303As required, the difference of the last iteaticn1に2、1:んり1こメ|

Answered: Image /qna-images/answer/4ef1be0e-9798-463a-b82b-a823e7fe0f66.jpg

Answered: Answer the following using Jacobi…

Answer the following using Jacobi Method. Show complete solutions. 2.) 9x1 - 13x2 + 4x3 = 111 4x1 + 22x2 -13x3 = -128 8x1 + 8x2 + 17x3 = 10 This is the example/guide that might help.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter9: Quadratic Functions And Equations

Section9.7: Solving Systems Of Linear And Quadratic Equations

Problem 30HP

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Question

Answer the following using Jacobi Method. Show complete solutions.

2.) 9x₁ - 13x₂ + 4x₃ = 111
4x₁ + 22x₂ -13x₃ = -128
8x₁ + 8x₂ + 17x₃ = 10

This is the example/guide that might help.

Step 3. Perform iterction until the values af
System of Linear Equations (Iterative Methads)
Iterative methads ave based on successive
improvement of initial quesser for the sdlution
ITERATIVE METHUDI : JACORI METHOD
Step 1. Rewrite the system
Step 2. Initialize
a value for the unknouns
of zeru.
tep 3. Perform iterction until the values al
the unknawn dan't divevge anymore.
falut
Example:
A 3xty-Z =3
2×+4y+zニフ
Solution:
そtん-e = メ
Y=7-2x-Z
4
Z:4-xty
スキメーh
: x:0; y=0,2=0
Ist Itercition
X,こ3-0+O
3
Y.= 7-2(0) - (0?
=1.75
Z,?4-04 O
4
2ND ITERAION:
メ2ラーy,ナ21-3-175+l>0.75
3
3
Y2:1-2x,*2フー2-D.1
そz: 4-Xty、 4-1t15
4-1+1.75
=1.1875

Sheuld oo be less than 0.005,
5 decimdl
3RD ITERATION:
メッ=3- y2t2,
%3D
3-1+1.1875
=1.0625
%3D
Yo:フ-2x, -Z2
7-210.75)-1-1875
こ
1.078125
2,- 4-メetyz 4 - C0-75) +|
%3D
i,0625
4
'Iteration
1
1.75
2.
0-75
|-1875
3
1.0425
1.078125
U -994792 0.953125 1.003906
10625
4
1.016927
1-001628 0-989583
0-995985 0.994141 0.990175
0.09953
7
1-000676
1.00303
As required, the difference of the last iteaticn
1に2、1:んり1こメ
|

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