Answers: (a) The force-couple system at O: R = ( i i+ i j) Ib Mo = i k Ib-in. (b) The line of action of the single resultant R: On the x-axis x = in. i On the y-axis y= in.
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- The force-couple system acting at O is equivalent to the wrench acting at A. If R=600i+1400j+700klb and |C|=1200lbft, determine CR.The steering column of the rack-and-pinion steering mechanism lies in the xz-plane. The tube AB of the steering gear is attached to the automobile chassis at A and B. When the steering wheel is turned, the assembly is subjected to the four couples shown: the 3-N m couple applied by the driver to the steering wheel, two 1.8-N m couples (one at each wheel), and the couple formed by the two forces of magnitude F acting at A and B. If the resultant couple acting on the steering mechanism is zero, determine F and the angle (the magnitude and direction of the bearing reactions).A 160-lb force P is applied at point A of a structural member.Replace P with (a) an equivalent force-couple system at C, (b) an equivalent system consisting of a vertical force at B and a second force at D.
- Given the picture below, if If L=80.0 N and A=60.0N, what is the fource couple at C equivalent to the 2 forces ?Example 2 - Home work Determine the moment produced by force Fabout segment AB of the pipe assembly . Express the result as a Cartesian vector . F = 1-201 + 10 + 15kN 4 m 4 mAn 8-m long cantilever beam is loaded with vertical forces A = 60 kN and B = 108 kN, separated by a distance d = 5.6 m, as shown. Replace the two forces with a single equivalent force R and determine the distance x-bar (x¯) from the left end of the beam to the line of action of R.
- Given a 2-D force system with geometry as shown. Find the magnitude of the equivalent couple moment (Nm) acting at O if P = 501 N , Q = 301 N, and T = 425 N .An overhead view of a portion of an exercise machine is shown. If the tension in the cable is T = 750 N, determine the equivalent force-couple system at (a) point B and at (b) point O.1. Determine the equivalent force-couple system at A of the system shown on the figure.
- For the given couple-force system shown, determine the vertical component of P.P= 331 KN Q= 40 KN R=65 KN-m Z=253 KNAnswer for the 1st part of the problem. magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downwUsing the component method, find the complete resultant of the following forces: F= 2m, 40° N of E, and G = 4m at 127° counterclockwise from East?