Any area that is below the x-axis is considered to be --Select-- v and the area above the x-axis is considered to be -Select-- v. Let A be the area of the triangle below the x-axis, and B be the area of the triangle above the x-axis. Then in terms of A and B, [(ex - 2) dx --Seleck 2A B-A 2B A-B 10 B -3 -1 2 3 A -10 -20 Before we can find the base length of each triangle, we need to find the x-intercept of the line. Find the x- intercept by solving 8x - 2 =| x-intercept

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 9P: A soda can is made from 40 square inches of aluminum. Let x denote the radius of the top of the can,...
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the select answers are 
zero 
negative 
and positive 

 

Any area that is below the x-axis is considered to be -Select- v and the area above the x-axis is considered
to be -Select-- v. Let A be the area of the triangle below the x-axis, and B be the area of the triangle
above the x-axis. Then in terms of A and B,
(ox - 2) dx =-Seleck-- v
-Select-
2A
В -А
2B
A -B
10
B
-3
-1
1
2 3
A
- 10
- 20
Before we can find the base length of each triangle, we need to find the x-intercept of the line. Find the x-
intercept by solving 8x - 2 = |
x-intercept
Transcribed Image Text:Any area that is below the x-axis is considered to be -Select- v and the area above the x-axis is considered to be -Select-- v. Let A be the area of the triangle below the x-axis, and B be the area of the triangle above the x-axis. Then in terms of A and B, (ox - 2) dx =-Seleck-- v -Select- 2A В -А 2B A -B 10 B -3 -1 1 2 3 A - 10 - 20 Before we can find the base length of each triangle, we need to find the x-intercept of the line. Find the x- intercept by solving 8x - 2 = | x-intercept
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