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- (Numerical) Using the srand() and rand() C++ library functions, fill an array of 1000 floating-point numbers with random numbers that have been scaled to the range 1 to 100. Then determine and display the number of random numbers having values between 1 and 50 and the number having values greater than 50. What do you expect the output counts to be?Evaluate the following, assuming that letters have consecutive character codes. (int)'D' − (int)'A'Any character is entered through the keyboard, write a C program to determine whether the character entered is a capital letter, a small case letter, a digit or a special symbol. The following table shows the range of ASCII values for various characters. Characters ASCII Values A – Z 65 – 90 a – z 97 – 122 0 – 9 48 – 57 Special symbols 0 - 47, 58 - 64, 91 - 96, 123 – 127
- Please help to answer the min Here is the code #include using namespace std; int main() { int numbers[10]; int i; for (i=0;i>numbers[i]; int numbers2[10],j,k; for(i=0;ic) { max1=rep; c=top; } } cout<The variables x and p have been declared as floating-point variables. Note that the way the value of 1.234567890000 that we assigned to x is displayed under different output formats. The value of x is displayed as 1.234567880630 under %.12lf format, while the actual value assigned is 1.234567890000. This is because the variable x has been declared as a float that can store values only upto six decimal places. The variable m that has been declared as int is not able to store the value 54321 correctly. Instead, it contains some garbage. Since this program was run on a 16-bit machine, the maximum value that an int variable can store is only 32767. However, the variable k (declared as unsigned) has stored the value 54321 correctly. Similarly, the long int variable n has storedt he value 1234567890 correctly. The value 9.87654321 assigned to y declared as double has been stored correctly but the valueis printed as 9.876543 under %lf format. Note that unless specified otherwise, the printf…The variables x and p have been declared as floating-point variables. Note that the way the value of 1.234567890000 that we assigned to x is displayed under different output formats. The value of x is displayed as 1.234567880630 under %.12lf format, while the actual value assigned is 1.234567890000. This is because the variable x has been declared as a float that can store values only upto six decimal places.The variable m that has been declared as int is not able to store the value 54321 correctly. Instead, it contains some garbage. Since this program was run on a 16-bit machine, the maximum value that an int variable can store is only 32767. However, the variable k (declared as unsigned) has stored the value 54321 correctly. Similarly, the long int variable n has storedt he value 1234567890 correctly.The value 9.87654321 assigned to y declared as double has been stored correctly but the valueis printed as 9.876543 under %lf format. Note that unless specified otherwise, the printf…
- (Temperature Conversions) Write a program that converts integer Fahrenheit temperaturesfrom 0 to 212 degrees to floating-point Celsius temperatures with 3 digits of precision. Perform thecalculation using the formulacelsius = 5.0 / 9.0 * (fahrenheit - 32);The output should be printed in two right-justified columns of 10 characters each, and the Celsiustemperatures should be preceded by a sign for both positive and negative values.Do some research to find at least two characters in the Extended ASCII character set, and the keyboard shortcuts that allow you to enter those characters directly from the keyboard. If possible, the characters should include letters in your name from question 1, otherwise add some new characters. Type the characters, AND the shortcuts you used. For example: Jôhn Bénoït (option-i, o), (option-e, e), (option-u, i).C++ Fix this code so that it displays in the format like the image shown where the principal and rate should have a fixed precision of 2 for each of the five percentages 5%,6%,7%,8%,9%,10%. The amount of the deposit should not have the fixed precision and should remain in the decimal format. #include <iostream>#include <iomanip>#include <cmath>using namespace std; int main(){double principal{ 1000 };double rate{ 0.05 }; for (rate; rate <= 0.10; rate += 0.01) {cout << "" << endl;cout << "Initial principal: " << principal << endl;cout << "Interest Rate: " << rate * 100 << "%" << endl;cout << setw(4) << "Year" << setw(20) << "Amount on deposit" << endl;for (unsigned int year{ 1 }; year <= 10; year++) {double amount = principal * pow(1.0 + rate, year); cout << setw(4) << year << setw(20) << amount << endl; }}}
- please write the code using only "C" code. Don't use "c++" and "c#".C language # ASCII Table Project * output all bytes from 0 to 255 * if it represents a printable character, print the actual character * if it is not a printable character, print a dash ("-") instead * print out the hexadecimal value of the byte* format the output into 8 columns (one column per byte) * line up all the columns ## TestsWrite at least one unit test. _This implies that you have at least one function you call._ There are at least two functions you could write (based on the product definition)(Data processing) Write C++ code sections to make the following decisions: a. Ask for two integer temperatures. If their values are equal, display the temperature; otherwise, do nothing. b. Ask for character values letter1 and letter2, representing uppercase letters of the alphabet, and display them in alphabetical order. c. Ask for three integer values, num1, num2, and num3, and display them in decreasing order.