Applying Kirchhoff's Laws to the circuit shown, a R1 R2 I2 R3 13 + E3 E1 E2 b Node a: – 1- 12-13=0 Node b: 1 + /2 + /3=0 Left loop: – R1 + /½R2= - E1 – E2 Right loop: - I2R2+ I3R3= E2+ E3 If R1 = 40, R2=6 N, R3=8 N, &1 = 6 V, E2= 12 V, ɛ3=5 V, Solve the four equations simultaneously and determine for the currents in the circuit. Express your answers in four (4) decimal places. + +

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
Applying Kirchhoff's Laws to the circuit shown,
a
R1
R2
12
R3
13
E2
E3
+
b
Node a: - l1- 12-13=0
Node b: 1 + l2+ /3=0
Left loop: - 1Rị + /½R2= - E1 - E2
Right loop: - 12R2 + I3R3= E2+ ɛ3
If R1 = 4 0, R2 = 6 N, R3=8 N, ɛ1 = 6 V, E2 = 12 V, ɛ3 =5 V.
Solve the four equations simultaneously and determine for the currents in the circuit. Express your answers in four (4) decimal places.
+
+
Transcribed Image Text:Applying Kirchhoff's Laws to the circuit shown, a R1 R2 12 R3 13 E2 E3 + b Node a: - l1- 12-13=0 Node b: 1 + l2+ /3=0 Left loop: - 1Rị + /½R2= - E1 - E2 Right loop: - 12R2 + I3R3= E2+ ɛ3 If R1 = 4 0, R2 = 6 N, R3=8 N, ɛ1 = 6 V, E2 = 12 V, ɛ3 =5 V. Solve the four equations simultaneously and determine for the currents in the circuit. Express your answers in four (4) decimal places. + +
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