As a jet takes off with with a speed of 160 m/sec at an angle of 40 degrees. It has it's shadow racing below casted by the sun, which is directly overhead. How fast is the shadow moving?  Equations given to possibly use: d= distnace v= velocity t=time v0=intitial velocity a=acceleration d = vt v = v0 + at d = v0t + 12at2 v2 = v02 + 2ad a2 + b2 = c2 (pythagorium theorum for a triangle)sinθ = yR; cosθ = xR; tanθ = yx

Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
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Chapter3: Vectors
Section: Chapter Questions
Problem 3.61AP: Lei A = 60.0 cm at 270 measured from the horizontal. Let B = 80.0 cm at some angle . (a) Find the...
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As a jet takes off with with a speed of 160 m/sec at an angle of 40 degrees. It has it's shadow racing below casted by the sun, which is directly overhead. How fast is the shadow moving? 

Equations given to possibly use: d= distnace v= velocity t=time v0=intitial velocity a=acceleration

d = vt

v = v0 + at
d = v0t + 12at2
v2 = v02 + 2ad
a2 + b2 = c2 (pythagorium theorum for a triangle)
sinθ = yR; cosθ = xR; tanθ = yx 

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