As shown in the figure below, a box of mass m = 61.0 kg (initially at rest) is pushed a distance d = 83.0 m across a rough warehouse floor by an applied force of FA = 228 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) (a) work done by the applied force WA 30° (b) work done by the force of gravity Wg J (c) work done by the normal force W J (d) work done by the force of friction W₁ = J W Net (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. J rough surface Net (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. WN J

icon
Related questions
Question
Please copy paste ans other wise down vote
As shown in the figure below, a box of mass m = 61.0 kg (initially at rest) is pushed a distance d = 83.0 m across a rough
warehouse floor by an applied force of FA = 228 N directed at an angle of 30.0° below the horizontal. The coefficient of
kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your
answer to the nearest multiple of 10.)
(a) work done by the applied force
WA
(b) work done by the force of gravity
W =
9
(c) work done by the normal force
WN =
(d) work done by the force of friction
Wf =
(e) Calculate the net work on the box by finding the sum of all the works done by each individual force.
W Net
=
rough surface
wwwwwwwwwwwwww
d
(f) Now find the net work by first finding the net force on the box, then finding the work done by this net force.
W Net
=
Transcribed Image Text:As shown in the figure below, a box of mass m = 61.0 kg (initially at rest) is pushed a distance d = 83.0 m across a rough warehouse floor by an applied force of FA = 228 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) (a) work done by the applied force WA (b) work done by the force of gravity W = 9 (c) work done by the normal force WN = (d) work done by the force of friction Wf = (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. W Net = rough surface wwwwwwwwwwwwww d (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. W Net =
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer