At the instant when the current in an inductor is increasing at a rate of 6.35x10-2 A/s, the magnitude of the self-induced emf is 1.55x10-2 V. Part A What is the inductance of the inductor? L = Submit My AnswersGive Up Part B H If the inductor is a solenoid with 395 turns, wh ? e = Wb
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Help to solve the part (B) only.
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