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Q: rewite usung for loop
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Types of Loop
Loops are the elements of programming in which a part of code is repeated a particular number of times. Loop executes the series of statements many times till the conditional statement becomes false.
Loops
Any task which is repeated more than one time is called a loop. Basically, loops can be divided into three types as while, do-while and for loop. There are so many programming languages like C, C++, JAVA, PYTHON, and many more where looping statements can be used for repetitive execution.
While Loop
Loop is a feature in the programming language. It helps us to execute a set of instructions regularly. The block of code executes until some conditions provided within that Loop are true.
rewrite the highlighted enhanced for loop as a for loop
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- Complete the private combinations method. Modify the code so that it is possible to compute combinations(“ABCD”,2) with fewer than 20 calls and combinations(“ABCDE”,3) with fewer than 30 calls. import static org.junit.Assert.*; import java.util.ArrayList; import org.junit.Test; /** * Recursive computation of all combinations of k characters from a string s. * */public class Combinations { private static int recusiveCalls = 0; /** * Generate all combinations of the characters in the string s with length * k. * * @param s * a string. * @param k * the length of the combinations * @return a list of all of the combinations of the strings in s. */ public static ArrayList<String> combinations(String s, int k) { return combinations("", s, k); } /** * Recursive Problem Transformation: * * Generate all combinations of length k of the characters in rest prefixed * with the characters in…InfoProcessorTest.java import java.util.*; /** * * Class to process and extract information from a list of lines. * */ public class InfoProcessorTest { /** * * List of lines to process. * */ private ArrayList<String> lines =new ArrayList<String>(); /** * * Creates InfoProcessor with given list of lines. * * @param lines to process * */ public InfoProcessorTest(ArrayList<String> lines) { this.lines = lines; } /** * * Gets the course name from the list of lines. * * First, finds the line that starts with "Course:". * * Second, gets the String on the very next line, which should be the course * name. * * Third, returns the String from the method. * * * * Hint(s): * * - Use the getNextStringStartsWith(String str) method to find the course name * * * * Example(s): * * - If the ArrayList<String> lines contains: "Course:" and "CIT590", and we * call * * getCourseName(), we'll get "CIT590". * * * * - If the ArrayList<String> lines contains: "Course:"…public class Tester{ public static void main(String[] args) { Segment[] segments = { new Segment(1, 5), // measure 4 new Segment(5, 1), // measure 4 new Segment(1, 1), // measure 0 new Segment(1, 3) // measure 2 }; System.out.println(average(segments)); System.out.println("Expected: 2.5"); } /** Computes the average of the measures of the given objects. @param objects an array of Measurable objects @return the average of the measures */ public static double average(Measurable[] objects) { if (objects.length == 0) { return 0; } double sum = 0; for (Measurable obj : objects) { sum = sum + obj.getMeasure(); } return sum / objects.length; }} /** Describes any class whose objects can be measured.*/public interface Measurable{ /** Computes the measure of the object. @return the measure */ double getMeasure();} The Segment…
- For any element in keysList with a value greater than 40, print the corresponding value in itemsList, followed by a semicolon (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20;30; import java.util.Scanner; public class Compare { public static void main(String args[]) {final int SIZE_LIST = 4;int[] keysList = new int[SIZE_LIST];int[] itemsList = new int[SIZE_LIST];int i;Scanner input = new Scanner(System.in); keysList[0] = input.nextInt();keysList[1] = input.nextInt();keysList[2] = input.nextInt();keysList[3] = input.nextInt(); itemsList[0] = input.nextInt();itemsList[1] = input.nextInt();itemsList[2] = input.nextInt();itemsList[3] = input.nextInt(); /* Your code goes here */ System.out.println();} }I need help with fixing this java program as described in the image below: LablProgram.java: import java.util.Scanner; public class LabProgram { /* TODO: Write recursive printLinkedList() method here. */ public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int size; int value; size = scnr.nextInt(); value = scnr.nextInt(); IntNode headNode = new IntNode(value); // Make head node as the first node IntNode lastNode = headNode; // Node to add after IntNode newNode = null; // Node to create // Insert the second and the rest of the nodes for (int n = 0; n < size - 1; ++n) { value = scnr.nextInt(); newNode = new IntNode(value); lastNode.insertAfter(newNode); lastNode = newNode; } // Call printLinkedList() with the head node printLinkedList(headNode); }} intNode.java: public class IntNode { int dataVal; private…Find the index of the first negative numberIntegerListUtils.java import java.util.ArrayList; public class IntegerListUtils { /** * Finds the index of the first negative number in the list. * * @param numbers a list of integers * @return the index of the first negative number, or -1 if no negative number found */ public static int findIndexOfFirstNegative(ArrayList<Integer> numbers) { // complete this method }}
- True or false linear probing selects "locations" 1, 2, 4, 9, 16, 25 java allows overloaded "function" to be declared in a data type called classes. Java allows multiple inheritance Any iterative function can be implemented recursively. Typically, recursive sorts are more efficient than iterative sorts.import java.util.*;class Arraylist{public static void main(String args[]){ArrayList obj = new ArrayList();obj.add("A");obj.add("B");obj.add("C");obj.add(1, "D");System.out.println(obj);}} What will the given code prints on the output screen.Artificial Intelligence - Local Search Starting from a randomly generated state of the 15-puzzle game, steepest-ascent hill-climbing (the vanilla version of hill-climbing search) gets stuck 76% of the time, i.e., solving only 24% of problem instances. But it works very quickly, i.e., it takes just 6 steps on average when it succeeds and 5 steps when it gets stuck. In contrast, if sideways moves are allowed, this raises the percentage of problem instances solved by hill-climbing from 24% to 81%, with the success at a cost: the algorithm averages roughly 7 steps for each successful instance and 32 steps for each failure. Now suppose that we are implementing random-restart hill climbing (i.e., if a search fails, it keeps to try, and try, until it gets a success) by the following two versions: one uses vanilla steepest-ascent hill climbing, and the other one uses hill climbing with sideways moves. Can you please tell which version of random-restart hill-climbing listed above runs faster…
- package sorting; import java.util.Arrays; import java.util.Random; import sorting.Heap; public class ComparisonSorter { public static void insertionSort(int[] arr) { for(int i=1;i<arr.length;i++) { int j = i-1; int toPlace = arr[i]; while(j>=0&&arr[j]>toPlace) { arr[j+1] = arr[j]; j--; } arr[j+1] = toPlace; } } public static void mergeSort(int [] arr) { mergeSortRecurse(arr,0,arr.length-1); } private static void mergeSortRecurse(int[] arr, int start, int end) { if(start>=end) return; int mid = start + ((end-start)/2); mergeSortRecurse(arr,start,mid); mergeSortRecurse(arr,mid+1,end); merge(arr,start,mid,end); } private static void merge(int[] arr, int start, int mid, int end) { int leftSize = mid - start +1; int rightSize = end - mid; int[] left = new int[leftSize+1]; int[] right = new int[rightSize+1]; int leftIndex; int rightIndex; for(leftIndex = 0; leftIndex<leftSize;leftIndex++) left[leftIndex] = arr[start+leftIndex]; for(rightIndex = 0;…package sorting; import java.util.Arrays; import java.util.Random; import sorting.Heap; public class ComparisonSorter { public static void insertionSort(int[] arr) { for(int i=1;i<arr.length;i++) { int j = i-1; int toPlace = arr[i]; while(j>=0&&arr[j]>toPlace) { arr[j+1] = arr[j]; j--; } arr[j+1] = toPlace; } } public static void mergeSort(int [] arr) { mergeSortRecurse(arr,0,arr.length-1); } private static void mergeSortRecurse(int[] arr, int start, int end) { if(start>=end) return; int mid = start + ((end-start)/2); mergeSortRecurse(arr,start,mid); mergeSortRecurse(arr,mid+1,end); merge(arr,start,mid,end); } private static void merge(int[] arr, int start, int mid, int end) { int leftSize = mid - start +1; int rightSize = end - mid; int[] left = new int[leftSize+1]; int[] right = new int[rightSize+1]; int leftIndex; int rightIndex; for(leftIndex = 0; leftIndex<leftSize;leftIndex++) left[leftIndex] = arr[start+leftIndex]; for(rightIndex = 0;…For any element in keysList with a value smaller than 50, print the corresponding value in itemsList, followed by a space. Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 10 40 import java.util.Scanner; public class Compare { public static void main(String args[]) { final int SIZE_LIST = 4; int[] keysList = new int[SIZE_LIST]; int[] itemsList = new int[SIZE_LIST]; int i; Scanner input = new Scanner(System.in); keysList[0] = input.nextInt(); keysList[1] = input.nextInt(); keysList[2] = input.nextInt(); keysList[3] = input.nextInt(); itemsList[0] = input.nextInt(); itemsList[1] = input.nextInt(); itemsList[2] = input.nextInt(); itemsList[3] = input.nextInt(); //answer// System.out.println(); } }