Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 54% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.21 a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. O A. Reject Ho because the P-value is greater than a. OB. Reject Ho because the P-value is less than or equal to a. OC. Fail to reject Ho because the P-value is less than or equal to a. OD. Fail to reject Ho because the P-value is greater than a.
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- For the given value of α and observed significance level (p -value), indicate whether the null hypothesis would be rejected.α = 0.01, p- value = 0.09 Reject H0 Fail to reject H0If, in a one-tail hypothesis test where H0 is only rejected in the upper tail, the p-value=0.6792 and ZSTAT=−0.47,what is the statistical decision if the null hypothesis is tested at the 0.07 level of significance? What is the statistical decision? Since the p-value is Less than or Greater than or equal to a= , Reject , Do not reject H0.In performing a hypothesis T-test, the p-value was 0.00046 and the significance level was 5%. What is the conclusion? Is it a,b,or c? a. Reject the null hypothesis and accept the alternate hypothesis b. Accept both the null hypothesis and alternate hypothesis c. Fail to reject the null hypothesis
- Based on certain data, a null hypothesis is rejected atthe 0.05 level of significance. Would it also be rejectedat the(a) 0.01 level of significance;(b) 0.10 level of significance?In testing hypotheses, which of the following would be strong evidence against the null hypothesis?a. Obtaining data with a test statistic of small magnitude.b. Obtaining data with a small P-value.c. Obtaining data with a large P-value.d. Using a large level of significance, α.e. Using a small level of significance, αA fast-food restaurant claims that a small order of french fries contains 120 calories. A nutritionist is concerned that the true average calorie count is higher than that. The nutritionist randomly selects 35 small orders of french fries and determines their calories. The resulting sample mean is 155.6 calories, and the pp-value for the hypothesis test is 0.00093. Which of the following is a correct interpretation of the p-value? A)If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or more. B) If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or less. C)If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or more, or a sample mean of 84.4 calories or less. .D)If the population mean is 155.6 calories, the p -value of 0.00093…
- If a researcher obtained a P-value of 0.01 for a hypothesis test that has a significance level of 0.05, what conclusion should the researcher make? 1 The null hypothesis should not be rejected. 2 The alternative hypothesis should not be rejected. 3 The null hypothesis should be rejected. 4 The alternative hypothesis should be rejected. 5 The null hypothesis must be false.Use the dataset HT_2448.xls. Using Excel, conduct a t-test (at the alpha = 0.01 significance level) on whether the mean of X1 is equal to 100. What do you conclude from this sample data? Is the population mean equal to 100? Group of answer choices: a-You cannot reject the null hypothesis. You conclude that the population mean is equal to 100. b-You reject the null hypothesis. You conclude that the population mean is equal to 100. c-You reject the null hypothesis. You conclude that the population mean is not equal to 100. d-You cannot reject the null hypothesis. You conclude that the population mean is not equal to 100. Data set HT_2448.xls X1 X2102.04 96.13100.47 97.63103.17 95.4295.09 104.41103.81 102.0895.36 103.33103.38 112.25100.26 96.9397.24 100.1999.61 102.7096.00 106.94100.69 102.29100.50 100.0098.81 97.6795.15 99.09100.01 98.57102.88 97.70101.36 108.11103.05 106.9496.17…Given the following null and alternative hypotheses H0: µ1 - µ2 = 0 HA: µ1 - µ2 ≠ 0 and the following sample information Sample 1 Sample 2 n1 = 125 n2 = 120 s1 = 31 s2 = 38 x1 = 130 x2 = 105 Develop the appropriate decision rule, assuming a significance level of 0.05 is to be used. Test the null hypothesis and indicate whether the sample information leads you to reject or fail to reject the null hypothesis. Use the test statistic approach.