Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 166 with 20% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. =         < p <

Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

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Q: Express the confidence interval 60.2 % ± 3.1 % in the form of a trilinear inequality. % < p <

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Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: The value of z at a 99.5% confidence level is 2.807, which can be found by using the standard normal…

Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

A: Given: n=330p^=0.82 From the Standard Normal Table, the value of z* for 95% level is 1.96. The 95%…

Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

A: Given that  Sample size (n) = 324 Success proportion (P) = 33% = 0.33 Confidence level (C) = 95%…

Q: Express the confidence interval 45.5% ±3.3% in the form of a trilinear inequality. % < p <

A: Given confidence interval is 45.5% ± 3.3%

Q: Let represent the percentage of all students who received a grade of B given they were male. Use a…

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Q: Express the confidence interval 65.7%±8.3% in the form of a trilinear inequality.

A: Confidence interval gives range of values true population proportion is most likely to lie at given…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: We have given that  Sample size (n)=89 Number of favorable cases (X)=49  We have to find the…

Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

A: Solution

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: Since the question requires accurate results, I will use excel to solve this question.…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: Solution: Let X be the number of successes and n be the sample size. From the given information,…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: given, p¯ =60%=0.60n=329at confidence level 99.9%,significance level(α)α=1-99.9%α=1-0.999α=.001by z…

Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…

A: Confidence interval:The (1-α) % confidence interval for proportion p is given by:

Q: Express the confidence interval 37.8 % ± 3.8 % in the form of a trilinear inequality. % <p <

A: We have to express the confidence interval from given data..

Q: Express the confidence interval 82.9 % ± 3.8 % in the form of a trilinear inequality. % <p<

A: The confidence interval formula of true population proportion p is (p̂ ± E), where p̂ is the sample…

Q: Express the confidence interval 507.1 + 150.3 in the form of a trilinear inequality.

A: The formula of confidence interval, CI = Sample mean +- margin of error

Q: The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on…

A: The degrees of freedom is, df=n-1=23-1=22 The degrees of freedom is 22. Computation of critical…

Q: Express the confidence interval 30.2 % ± 3.7 % in the form of a trilinear inequality. % <p < %

A: The given confidence interval is, The given confidence interval is in the form of p^±E  That is,…

Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…

A: Given that  Confidence level (C) = 90% = 0.90 Sample size (n) = 271 Number of successes (x)  = 70…

Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

A: Find z-critical value:…

Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

A: Given: Confidence level = 1 - α = 0.80 Significance level = α = 0.02 Sample size = n = 318 Sample…

Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: Here we need to find a 99.5% confidence interval for the population proportion p. Given sample size=…

Q: assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

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Q: Assume that a sample is used to estimate a population mean μ. Find the 80% confidence interval for a…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

A: From the given information,n= 195, P=66% or 0.66

Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

A: Given that  n=291 , X=82 Formula for confidence interval  C.I=(p  ± Zc √(p(1 - p)/n))

Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

A: Here number of samples , n = 227 positive samples , x = 92 So, sample proportion, p^ = 29227  =…

Q: Assume that a sample is used to estimate a population proportion P. Find the 99% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

A: Sample proportion Z-critical value:

Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

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Q: Express the confidence interval 25.7 % ± 4% in the form of a trilinear inequality. % < p < | %

A: An inference process is used to draw conclusions about the population mean for example hypothesis…

Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…

A: Given,Sample size(n)=272sample proportion(p^)=0.111-p^=1-0.11=0.89α=1-0.90=0.1α2=0.05Z0.05=1.645…

Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

A: From the given information, let X be the number of successes.  X = 74. Let n be the total number of…

Q: Let r represent the percentage of all female students who would receive a grade of B on this test.…

A: In this study there are totally 47 students are there out of which 9 female students who would…

Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval…

A: Given data, n=91 p=30%=0.30 z-value at 99% confidence is Zc=2.576

Q: Express the confidence interval 76.1 % + 7.9 % in the form of a trilinear inequality. % <p<

A: Solution Step 1 Given confidence interval is 76.1 % +/- 7.9% So ( 76.1℅ -7.9 %  , 76.1% + 7.9%) (…

Q: Assume that a sample is used to estimate a population mean μμ. Find the 80% confidence interval for…

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Q: Express the confidence interval 35.1 % ±6.7 % in the form of a trilinear inequality. % < p <

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Q: population proportion p. Find the 80% confidence interval for a sample of size 326 with 184…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval…

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