Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P70, the 70-percentile. This is the temperature reading separating the bottom 70% from the top 30%. P70 = °C (Round answer to three decimal places)

The kelvin is a unit of measurement for temperature; 0 K is absolute zero, the temperature at which all thermal motion ceases. Conversion from Fahrenheit to Kelvin is given by K=× (F-32)+273. The average daily temperature in Monrovia, Liberia, is 78.35°F with a standard deviation of 6.3°F. If a scientist converts Monrovia daily temperatures to the Kelvin scale, what will be the new mean and standard deviation? (A) Mean, 25.75 K; standard deviation, 3.5 K (B) Mean, 231.75 K; standard deviation, 3.5 K (C) Mean, 298.75 K; standard deviation, 3.5 K (D) Mean, 298.75 K; standard deviation, 258.72 K (E) Mean, 298.75 K; standard deviation, 276.5 K

Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%. P61 = °C Submit Question

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P80, the 80-percentile. This is the temperature reading separating the bottom 80% from the top 20%.P80 = °C

Assume that thermometer readings are normally distributed with a mean of 0degrees°C and a standard deviation of 1.00degrees°C. A thermometer is randomly selected and tested. (The given values are in Celsius​ degrees.)   Between -1.47and 1.76

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%.P61 =

Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. OB. Oc. z=1.50 z=2.25 z=1.50 z=2.25 z=1.50 z=2.25 The probability of getting a reading between 1.50°C and 2.25°C isO. (Round to four decimal places as needed.)

Assume that adults have IQ scores that are normally distributed with a mean of u= 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 91 and 119. Click to view page 1 of the table. Click to view page 2 of the table. ces The probability that a randomly selected adult has an IQ between 91 and 119 is (Type an integer or decimal rounded to four decimal places as needed.) Exp The use

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P30, the 30-percentile. This is the temperature reading separating the bottom 30% from the top 70%.P30 =       °C(Round answer to three decimal places)

Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P15, the 15th percentile. This is the bone density score separating the bottom 15% from the top 85%. Which graph represents P15? Choose the correct graph below. O A. 1 P15 Q The bone density score corresponding to P15 is (Round to two decimal places as needed.) B. P15 Q Q -C*** O C. A P15 O D. A P15 Q