Need help with math review question Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of1.00 C. A themometer is randomly selected and tested. For the case below, draw a sketch, and find theprobability of the reading. (The given values are in Celsius degrees.)Between 1.50 and 2.25Click to view page 1 of the table. Click to view page 2 of the table.Draw a sketch. Choose the correct graph below.OA.O B.OC.z=1.50 z-2.25z=1.50N3D2.25z=1.50z=2.25The probability of getting a reading between 1.50°C and 2.25°C is(Round to four decimal places as needed.) Standard Normal Table (Page 1)Standard Normal Table (Page 2)NEGATIVE z ScoresPOSITIVE z ScoresStandard Normal (z) Distribution: Cumulative Area from the LEFTStandard Normal (z) Distribution: Cumulative Area from the LEFT0004070804050708-150S3195714527956756064644368087157748677948078SO80$478san.52395359575361416517G8797224757 754978528153$120SS17Si60555759480.001559696966026000300046480684475564060004000400040006Co080004GE6420196700655469:5725%677272404667832COOS00050.169506945C00700077589770417995732430-29-28D012C01000140020002700370049C068 0066008707276478237675796700142881302500230023.00220030004000210028002182124186438ELESD0261461.4531as548577879044854508-2.60047004188300057O05200481291479292941895259616969397560078007300719049191629177931994419545963397069767981798579131107OC843222935792369370925192659279o136012901250122933294529345939493829495 95059591 49599967194290158020202560322O1540197D150019201469474943495350228028703590446os4802220281021202070262956496499575365693349582S664973297889625969997619812985498879913027402440J0703840475O5820708O6531020121034230239030105750465057106340233023403670455055996419678968697509803O31403920485059407219/199726973897440436o55704092021978397939808osos 049SA 0G06073598214326Gaso98389842985098841886198343846986198640868987198759878OB0B07307780764)07492324252627289898969619922990499099166-99361069918992099299927994599599969997799319934S601095(292105612511469FOOL319099409943994699521357as8715355621271492250446170157999539965935599669975995799619962 996599643401996799709978998499899971997299749981997599749976997799798676466998619492236254428772033209023892709osor.340920612.999819985998999929963124202432206251499879987998799919968998869569995999024512776$12124839992999299929993201032999399959997999399949994999499949995993599959995966699979996999696569996349997999799972666999799979998s97128639364168456242074090409452249204483Ind up50004880MAOI426114721NOTE For values of z above 3.49, use 09999 for the area.Common Citical ValuT these common values that result from interpolationNOTE For vales of z below -348 use 0 0o01 for the area"Use theseConfidence CriticalValue.Level7SEOreArearom interpolaion164525750.95000.901645score19625750.99500.95-L645 0soo0.99-2575

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Need help with math review question Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of1.00 C. A themometer is randomly selected and tested. For the case below, draw a sketch, and find theprobability of the reading. (The given values are in Celsius degrees.)Between 1.50 and 2.25Click to view page 1 of the table. Click to view page 2 of the table.Draw a sketch. Choose the correct graph below.OA.O B.OC.z=1.50 z-2.25z=1.50N3D2.25z=1.50z=2.25The probability of getting a reading between 1.50°C and 2.25°C is(Round to four decimal places as needed.) Standard Normal Table (Page 1)Standard Normal Table (Page 2)NEGATIVE z ScoresPOSITIVE z ScoresStandard Normal (z) Distribution: Cumulative Area from the LEFTStandard Normal (z) Distribution: Cumulative Area from the LEFT0004070804050708-150S3195714527956756064644368087157748677948078SO80$478san.52395359575361416517G8797224757 754978528153$120SS17Si60555759480.001559696966026000300046480684475564060004000400040006Co080004GE6420196700655469:5725%677272404667832COOS00050.169506945C00700077589770417995732430-29-28D012C01000140020002700370049C068 0066008707276478237675796700142881302500230023.00220030004000210028002182124186438ELESD0261461.4531as548577879044854508-2.60047004188300057O05200481291479292941895259616969397560078007300719049191629177931994419545963397069767981798579131107OC843222935792369370925192659279o136012901250122933294529345939493829495 95059591 49599967194290158020202560322O1540197D150019201469474943495350228028703590446os4802220281021202070262956496499575365693349582S664973297889625969997619812985498879913027402440J0703840475O5820708O6531020121034230239030105750465057106340233023403670455055996419678968697509803O31403920485059407219/199726973897440436o55704092021978397939808osos 049SA 0G06073598214326Gaso98389842985098841886198343846986198640868987198759878OB0B07307780764)07492324252627289898969619922990499099166-99361069918992099299927994599599969997799319934S601095(292105612511469FOOL319099409943994699521357as8715355621271492250446170157999539965935599669975995799619962 996599643401996799709978998499899971997299749981997599749976997799798676466998619492236254428772033209023892709osor.340920612.999819985998999929963124202432206251499879987998799919968998869569995999024512776$12124839992999299929993201032999399959997999399949994999499949995993599959995966699979996999696569996349997999799972666999799979998s97128639364168456242074090409452249204483Ind up50004880MAOI426114721NOTE For values of z above 3.49, use 09999 for the area.Common Citical ValuT these common values that result from interpolationNOTE For vales of z below -348 use 0 0o01 for the area&#34;Use theseConfidence CriticalValue.Level7SEOreArearom interpolaion164525750.95000.901645score19625750.99500.95-L645 0soo0.99-2575

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