Assume the following processes are scheduled in the CPU using the round-robin scheduling with time quanta 2 ms. All the processes execute the same code that involves using a SPINLOoCK mutex (spinlock means the process busy-waits until other process releases and it acquires the mutex. And this waiting happens inside the acquire statement). The code is as follows: acquire(&lock) r critical section */ release(&lock) * remainder section "/ Process No Arrival Time Burst Time PO 6ms P1 X 6ms P2 Y 6ms P3 6ms The CPU burst time for the critical section part of the code is 3ms, and for the remainder section, it is again 3ms. Thus, all processes CPU burst time would be 6ms if they do not wait to acquire the mutex lock. Consider, X = 3, Y = 3, Z = 3. Select the processes that will be waiting to acquire the mutex at time 10ms. There is no partial marking for this question. P1 O P2 O P3 P4 Submit You have used 0 of 1 attempt Save

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· (graded)
Assume the following processes are scheduled in the CPU using the round-robin scheduling with time quanta 2 ms. All the processes execute the same
code that involves using a SPINLOCK mutex (spinlock means the process busy-waits until other process releases and it acquires the mutex. And this
waiting happens inside the acquire statement). The code is as follows:
acquire(&lock)
/* critical section */
release(&lock)
/* remainder section */
Process No
Arrival Time
Burst Time
PO
6ms
P1
X
6ms
P2
Y
6ms
P3
6ms
The CPU burst time for the critical section part of the code is 3ms, and for the remainder section, it is again 3ms. Thus, all processes' CPU burst time
would be 6ms if they do not wait to acquire the mutex lock.
Consider, X = 3, Y = 3, Z = 3.
Select the processes that will be waiting to acquire the mutex at time 10ms. There is no partial
marking for this question.
OP1
P2
O P3
O P4
Submit
You have used 0 of 1 attempt
Save
Transcribed Image Text:· (graded) Assume the following processes are scheduled in the CPU using the round-robin scheduling with time quanta 2 ms. All the processes execute the same code that involves using a SPINLOCK mutex (spinlock means the process busy-waits until other process releases and it acquires the mutex. And this waiting happens inside the acquire statement). The code is as follows: acquire(&lock) /* critical section */ release(&lock) /* remainder section */ Process No Arrival Time Burst Time PO 6ms P1 X 6ms P2 Y 6ms P3 6ms The CPU burst time for the critical section part of the code is 3ms, and for the remainder section, it is again 3ms. Thus, all processes' CPU burst time would be 6ms if they do not wait to acquire the mutex lock. Consider, X = 3, Y = 3, Z = 3. Select the processes that will be waiting to acquire the mutex at time 10ms. There is no partial marking for this question. OP1 P2 O P3 O P4 Submit You have used 0 of 1 attempt Save
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