CPU scheduler will decide which proce should be given the CPU for execution. For this it uses differe algorithm to choose among the proce: One among that algorithm is FC algorithm. In this algorithm the proce which arrivoc firot i a
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- Consider Context Switch time of 2 secs and modify below program accordingly Program: FCFS CPU SCHEDULING ALGORITHM:#include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n); for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}Modiflow y the beprogram given to include response time program;FCFS CPU SCHEDULING ALGORITHM #include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n); for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}Modiflow y the beprogram given to include response time program;FCFS CPU SCHEDULING ALGORITHM #include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n);for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0];for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}
- In this project, you'll implement one of the following CPU scheduling algorithms by writing a CPU simulator. Shortest Job First (SJF)(Non-preemptive)The shortest job first algorithm is a priority based scheduling algorithm that associates with each process the length of the process's next CPU burst. When CPU is available, it is assigned to the process that has the smallest next CPU burst. Shortest Remaining Time Next (SRTN)(Preemptive)The shortest remaining process next scheduling algorithm is the preemptive Shortest Job First algorithm. With this scheduling algorithm, the process in the ready queue with the shortest execution time is chosen to execute. If a "new process" arrives in the ready queue with a CPU service time less than the remaining time of the current process, preempt. First Come First Serve (FCFS) (recommended)The first come first serve algorithm is simplest CPU-scheduling algorithm. In this algorithm, the process at the head of the queue is allowed to execute until it…In executing Jobs A and B using the priority scheduling algorithm, what will happen ifboth jobs have:a. unequal priorities but equal CPU cycles?b.equal priorities but different CPU cvcles?In executing Jobs A and B using the priority scheduling algorithm, what will happen ifboth jobs have:a. unequal priorities but equal CPU cycles?b. equal priorities but different CPU cvcles?
- Given the list of processes, their CPU burst times, arrival times and priorities implement SJF,Priority and Round Robin scheduling algorithms on the processes with preemption. For each ofthe scheduling policies, compute and print the completion Time(CT), Turnaround Time(TAT),and Waiting Time(WT) for each process using C Programming.Waiting time: Processes need to wait in the process queue before execution starts and inexecution while they get preempted. Turnaround time: Time elapsed by each process to get completely served. (Difference betweensubmission time and completion time).Consider Context Switch time of 2 secs and modify below program accordingly. SJF CPU SCHEDULING ALGORITHM #include<stdio.h> #include<conio.h> using namespace std; int main() { int p[20], bt[20], wt[20], tat[20], i, k, n, temp; float wtavg, tatavg; printf("\nEnter the number of processes--"); scanf("%d", &n); for(i=0;i<n;i++) { p[i]=i; printf("Enter Burst Time for Process %d--", i); scanf("%d", &bt[i]); } for(i=0;i<n;i++) for(k=i+1;k<n;k++) if(bt[i]>bt[k]) { temp=bt[i]; bt[i]=bt[k]; bt[k]=temp; temp=p[i]; p[i]=p[k];…The ready queue is subdivided into many queues by the multilevel scheduling algorithm, and each of these queues has its own scheduling technique or policy. Choose one: Is it accurate or erroneous? The time a process spends waiting should be minimised by the CPU scheduler. Choose one: OFalse O True
- Consider Context Switch time of 2 secs and modify below program accordingly Program: SJF CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int p[20], bt[20], wt[20], tat[20], i, k, n, temp; float wtavg, tatavg;printf("\nEnter the number of processes--"); scanf("%d", &n);for(i=0;i<n;i++){p[i]=i;printf("Enter Burst Time for Process %d--", i); scanf("%d", &bt[i]);}for(i=0;i<n;i++)for(k=i+1;k<n;k++)if(bt[i]>bt[k]){temp=bt[i]; bt[i]=bt[k];bt[k]=temp;temp=p[i];p[i]=p[k];p[k]=temp;}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] =wt[i-1]+bt[i-1];tat[i] =tat[i-1]+bt[i];wtavg = wtavg + wt[i];tatavg = tatavg + tat[i];}printf("\n\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n"); for(i=0;i<n;i++)printf("\n\t P%d \t\t %d \t\t %d \t\t %d", p[i], bt[i], wt[i], tat[i]);printf("\nAverage Waiting Time--%f", wtavg/n);printf("\nAverage Turnaround Time--%f", tatavg/n); getch();}Argue, whether it is fair that some process p is not currently running, though p has all resources (except the CPU) needed to execute. (short answer is ok)When this option is available, the I/O queue should be prioritised above the process execution queue. In what ways may this be beneficial? Who knows what will take place if there is a disruption in the I/O. It is unclear at this time if this will have an effect on the maximum burst rate of the CPU. I'm not really clear on the point you're trying to make here.