Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memoryconfiguration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix)Logical Address FormatPhysical MemoryPhysical Address (starting)Page TableОхрppddddPage | FrameFrameSize (hex)Size (dec)2Охс000Ox1000065536pppp: page numberdddd: page offset11Оxd000Ox100006553632Охе000Ox10000655363Oxf000Ox1000065536Translate the following addresses:What is the physical address for 0x0002ffffWhat is the physical address for Ox0000abcd ?What is the logical address for Oxf000000f ?What is the logical address for Oxc000bbcc ?

Name: Assume variables have logical addresses with 16-bit page numbers and
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memoryconfiguration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix)Logical Address FormatPhysical MemoryPhysical Address (

The logical address is represented as combination of page number and page offset. physical address…

Engineering

Computer Science

Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Page Table Physical Memory Physical Address (starting) Oxppppdddd Page | Frame Frame Size (hex) Size (dec) Охс000 Ox10000 65536 pppp: page number dddd: page offset 1 1 Оxd000 Ox10000 65536 2 3 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for Ox0002ffff What is the physical address for 0x0000abcd ? What is the logical address for Oxf000000f ? What is the logical address for Oxc000bbcc ?

Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Page Table Physical Memory Physical Address (starting) Oxppppdddd Page | Frame Frame Size (hex) Size (dec) Охс000 Ox10000 65536 pppp: page number dddd: page offset 1 1 Оxd000 Ox10000 65536 2 3 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for Ox0002ffff What is the physical address for 0x0000abcd ? What is the logical address for Oxf000000f ? What is the logical address for Oxc000bbcc ?

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter10: Pointers

Section10.1: Addresses And Pointers

Problem 12E

See similar textbooks

Similar questions

The following data segment starts at memory address 1000h (hexadecimal) .data printString BYTE "ASSEMBLY IS FUN",0 moreBytes BYTE 25(DUP)0 dateIssued DWORD ? dueDate DWORD ? elapsedTime Word ? What is the hexadecimal address of dueDate ? a. 1045h b. 1029h c.1010h d. 102Dh
Modify vaddr.c and call it vaddr2.c . The new program should output the page number and offset for the given address using 1MB page size.#include #include int main(int argc, char *argv[]) { unsigned long page, offset, address; if(argc != 2) exit(1); address= atoll(argv[1]); page = address >> 12; /*calculating pages number*/ offset = address & 0xfff; /*calculating remaining offset*/ printf("The address %lu contains: \n", address); printf("page number = %lu\n",page); printf("offset = %lu\n", offset); return 0; }
Draw a picture illustrating the contents of memory, given the following data declarations: You need to mark all the memory addresses. Assume that your data segment starts at 0x1000 in memory. Name: .asciiz "Jim Bond!"Age: .byte 24Numbers: .word 11, 22, 33Letter1: .asciiz 'M' In this format HexadecimalAddress, Hex Value, Character/Number/Symbol, Binary Value, Decimal Value
Let's say that p is a pointer to memory and the next four bytes in memory (in hex) beginning at p's address are: 89 AB CD EF. After the following code is run on a little-endian computer what are the values of x, y, and the four bytes in memory beginning at p's address. Answer for x and y in four digits of upper-case hexadecimal (eg, 0AC6). Answer for memory as eight digits of upper-case hexadecimal with a single space between each byte (eg, 89 AB CD EF). x: y: mem at p:
28. _____ method is used to map logical addresses of variable length onto physical memory. a. Paging b. Overlays c. Segmentation d. Paging with segmentation
Draw a picture illustrating the contents of memory, given the following data declarations: You need to mark all the memory addresses. Assume that your data segment starts at 0x1000 in memory. Name: .asciiz "Jim Bond!"Age: .byte 24Numbers: .word 11, 22, 33Letter1: .asciiz 'M' In this format HexadecimalAddress, Hex Value, Character/Number/Symbol, Binary Value, Decimal Value ALREADY HAVE! marking all the memory addresses. Assuming that the data segment starts at 0x1000 in memory. The Memory Layout looks like Byte by Byte Address Data 0x1000 4a 0x1001 61 0x1002 6d 0x1003 65 0x1004 73 0x1005 00 0x1006 18 0x1007 00 0x1008 0b 0x1009 00 0x100a 00 0x100b 00 0x100c 21 0x100d 00 0x100e 00 0x100f 00 0x1010 14 0x1011 00 0x1012 00 0x1013 00 0x1014 4d arrow_forward Step 2 In mips 1 word is equal to 4 bytes. Address Data…
If the value 8 is stored in the memory location indicated by address 5, then what is the functional difference between copying the value 5 into cell 6 and copying the contents of cell 5 into cell 6?
Below is a list of 32-bit memory address references, given as memory addresses. 12, 720, 172, 8, 764, 352, 760, 56, 724, 176, 744You would like to access a cache with the given memory addresses. The size of cache is 23 = 8-blocks. Your task is to: (1) find out the binary address, (2) fill out the tag and index for each memory address and (3) indicate whether the access is hit or miss in the following table:
For the following loop, assume the array arr2[][] has never been referenced before in the code. Also assume that a cache line is 32 Bytes, and an int is 4 Bytes. 1. How many memory references are there?2. How many cache misses are there?
If the value 8 is stored at the memory location indicated by address 5, what is the difference between copying the contents of that location into location 6 and simply inserting the value 5 there?
instruction is in the first picture please give me only implementation of int L1lookup(u_int32_t address) and int L2lookup(u_int32_t address) cacheSim.h #include<stdlib.h>#include<stdio.h>#define DRAM_SIZE 1048576typedef struct cb_struct {unsigned char data[16]; // One cache block is 16 bytes.u_int32_t tag;u_int32_t timeStamp; /// This is used to determine what to evict. You can update the timestamp using cycles.}cacheBlock;typedef struct access {int readWrite; // 0 for read, 1 for writeu_int32_t address;u_int32_t data; // If this is a read access, value here is 0}cacheAccess;// This is our dummy DRAM. You can initialize this in anyway you want to test.unsigned char * DRAM;cacheBlock L1_cache[2][2]; // Our 2-way, 64 byte cachecacheBlock L2_cache[4][4]; // Our 4-way, 256 byte cache// Trace points to a series of cache accesses.FILE *trace;long cycles;void init_DRAM();// This function print the content of the cache in the following format for an N-way cache with M Sets// Set 0…
Please help! Please take a look at the code I have provided as a attachment to this question. Please comment each line of code of the differences between program 1 and 2. What happens when you subtract one pointer from another? Is it subtracting the two addresses, or something else? How do you know? What happens when you increment a pointer? Compare and contrast how C-strings are laid out in memory compared to arrays of integers. What's one similarity and one difference? Show how the individual bytes of this integer array are laid out in memory. Thanks!