The following byte sequence is the machine code of a program function compiled with the Y86- 64 instruction set. The memory address of the first byte is 0x300. Note that the byte sequence is written in hex-decimal form, i.e., each number/letter is one hex-decimal number representing 4 binary bits, and two numbers/letters represent one byte. 630030F3020000000000000030F11E000000000000007023030000000 00000601061316211761F0300000000000090- Please write out the assembly instructions (in Y86-64 instruction set) corresponding to the machine codes given by the above bytes sequence, and explain what this program function is computing. The machine has a little-endian byte ordering.

Suppose that x and y have byte values 0x69 (01101001) and Ox55 (01010101), respectively. Fill in the following table indicating the byte values of different C expressions in hex format (Hint: Result of C language logical and binary operations) c)-xl-y Value Ox d) x & ly Value Ox c) x 1 ly Value Ox d) x && -y Value Ox

In a certain computer program, two positive integers are added together, resulting in an overflow error. Which of the following best explains why the error occurs? A) The program attempted to perform an operation that is considered an undecidable problem. B) The precision of the result is limited due to the constraints of using a floating-point representation. C) The program can only use a fixed number of bits to represent integers; the computed sum is greater than the maximum representable value. D) The program cannot represent integers; the integers are converted into decimal approximations, leading to rounding errors.

Please write the lines that the code will print out. Assume the following addresses: - a in main has the address 1000-b in main has the address 1004 c in main has the address 1008 - d in main has the address 1012 - b in fooA has the address 2000 - a in fooA has the address 2008 int fooA (int* b, int& c, int a) { (*b) ++; c+ = 2; a + = 4; cout <<<<<<' <<<&Q<<< ""«a« ""<< b<< "" <<

The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…

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Complete the tables that follow to describe the memory addresses and values of each variable when the last statement in the ChangePasscode function is performed (right before the function exits). Note: Operating systems may use different rules for assigning memory addresses. For this worksheet let us assume that the compiler will use up the greater memory address first (e.g., if 0x7ffd151a1d58 and 0x7ffd151a1d5c are available, it will initialize variables in 0x7ffd151a1d5c first).

In a letter to the editor of CACM, Rubin (1987) uses the following code segment as evidence that the readability of some code with gotos is better than the equivalent code without gotos. This code finds the first row of an n by n integer matrix named x that has nothing but zero values. for \( (i=1 ; i<=n ; i++)\{ \) for \( (j=1 ; j<=n ; j++) \) if \( (x[i][j] !=0) \) goto reject; println (First all-zero row Show Transcribed Text Rewrite this code without gotos either in C or Java. Compare the readability of your code to that of the example code. No hand written solution and no image

Microprocessor8086 Write the assembly of Write on the data segment and create number1 and number2 variables in byte size and initialize the variables Then compute the sum ,subtraction,multiplication and division of the defined variables and load the values to the variables which you create on the data segment Perform the operations below in sequence with defined on the data segment numbers in array Find the sum of array and average of array Find the maximum and minimum numbers of array If it’s possible on emu8086 app