Assuming 100% dissociation, calculate the freezing point (?f) and boiling point (?b) of 2.09 ? CaCl2(aq).(answers in degree Celsius) Colligative constants can be found in the Table below.

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter17: Spontaneity, Entropy, And Free Energy
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Problem 128IP: Some nonelectrolyte solute (molar mass = 142 g/mol) was dissolved in 150. mL of a solvent (density =...
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Assuming 100% dissociation, calculate the freezing point (?f) and boiling point (?b) of 2.09 ? CaCl2(aq).(answers in degree Celsius)

Colligative constants can be found in the Table below.

Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
value Normal boiling
Kf value* Normal freezing K b
point ( °C)
Solvent
Formula
(°C/ m )
(°C/ m )
point ( °C)
water
H 20
1.86
0.00
0.512
100.00
benzene
C 6 H 6
5.12
5.49
2.53
80.1
cyclohexane C 6 H 12
C 2 H 60
20.8
6.59
2.92
80.7
ethanol
1.99
|-117.3
1.22
78.4
carbon
CCI 4
29.8
-22.9
5.03
76.8
tetrachloride
camphor
С 10 Н 16 0 37.8
176
Transcribed Image Text:Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: value Normal boiling Kf value* Normal freezing K b point ( °C) Solvent Formula (°C/ m ) (°C/ m ) point ( °C) water H 20 1.86 0.00 0.512 100.00 benzene C 6 H 6 5.12 5.49 2.53 80.1 cyclohexane C 6 H 12 C 2 H 60 20.8 6.59 2.92 80.7 ethanol 1.99 |-117.3 1.22 78.4 carbon CCI 4 29.8 -22.9 5.03 76.8 tetrachloride camphor С 10 Н 16 0 37.8 176
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