"Assuming no fiction, what is the acceleration of the system of the following figure (in m/s2)?"4 kg1 kg What is the tension in the cord of the previous problem2N4 N6 N8 NNone of these

Name: "Assuming no fiction, what is the acceleration of the system of the f
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Description: "Assuming no fiction, what is the acceleration of the system of the following figure (in m/s2)?"4 kg1 kg What is the tension in the cord of the previous problem2N4 N6 N8 NNone of these

Mass of the first block = m1 = 4 kg Mass of the second block = m2 = 1 kg Acceleration = a =? Tension…

Answered: "Assuming no fiction, what is the…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter4: Forces In One Dimension

Section: Chapter Questions

Problem 56A

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"Assuming no fiction, what is the acceleration of the system of the following figure (in m/s2)?"
4 kg
1 kg

What is the tension in the cord of the previous problem
2N
4 N
6 N
8 N
None of these

Expert Solution

Given Data

Mass of the first block = m₁ = 4 kg

Mass of the second block = m₂ = 1 kg

Acceleration = a =?

Tension = T =?

Solution: For Acceleration

Free Body Diagrams:

For m₁ = 4 kg:

Using newton's second law,

T = m₁a . . . . . (i)

For m₂ = 1 kg:

Using newton's second law,

W - T = m₂a

m₂g - T = m₂a . . . . . (ii)

Substituting equation (i) in equation (ii),

m₂g - m₁a = m₂a

Therefore, $a = \frac{m_{2} g}{m_{1} + m_{2}}$

Substituting the values,

$a = \frac{1 \times 9.8}{4 + 1}$

$a =$ 1.96 m/s² $\approx$ 2 m/s²

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