At 15 °C, the following concentrations were found for the gases in an equilibrium mixture for the reaction N20(g) + NO2(3) = 3NO(g) [NO2] = 0.15 M, [NO] = 1.1 × 10-8 M, and [N20] = 0.033 M. What is the value of K, for this reaction?
At 15 °C, the following concentrations were found for the gases in an equilibrium mixture for the reaction N20(g) + NO2(3) = 3NO(g) [NO2] = 0.15 M, [NO] = 1.1 × 10-8 M, and [N20] = 0.033 M. What is the value of K, for this reaction?
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 71GQ: The equilibrium constant for the butane iso-butane equilibrium at 25 C is 2.50. Calculate rG at...
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![At 15 °C, the following concentrations were found for the gases in an equilibrium mixture for the reaction
N20(g) + NO2(s)
= 3NO७)
[NO2] = 0.15 M, [NO] = 1.1 x 10-8 M, and [N20] = 0.033 M.
What is the value of K, for this reaction?
Enter your answer in scientific notation.
Kp
i
x 10
i](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34784e04-15c4-48e3-8d00-89b2475118ca%2F00753645-8839-4acb-8b8f-3106067cc879%2Ft369wa_processed.png&w=3840&q=75)
Transcribed Image Text:At 15 °C, the following concentrations were found for the gases in an equilibrium mixture for the reaction
N20(g) + NO2(s)
= 3NO७)
[NO2] = 0.15 M, [NO] = 1.1 x 10-8 M, and [N20] = 0.033 M.
What is the value of K, for this reaction?
Enter your answer in scientific notation.
Kp
i
x 10
i
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