4. answer it so i can double check, asap At 20 ml of the titrant.A) 10.23B 11.7812.23D13.78 A 50.00 ml of 0.0275 M HCl solution was titrated with 0.1500 M NaOH. Calculate the pH of the analyte solution in thespecified volumes of the titrant added.

Volume of HCl = 50.00 ml Molarity of HCl = 0.0275 M Molarity of NaOH = 0.1500 M Volume of NaOH = 20…

Answered: At 20 ml of the titrant. A) 10.23 B…

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At 20 ml of the titrant. A) 10.23 B 11.78 12.23 D 13.78

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter15: Additional Aqueous Equilibria

Section: Chapter Questions

Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

4. answer it so i can double check, asap

At 20 ml of the titrant.
A) 10.23
B 11.78
12.23
D
13.78

A 50.00 ml of 0.0275 M HCl solution was titrated with 0.1500 M NaOH. Calculate the pH of the analyte solution in the
specified volumes of the titrant added.

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