At 20.0 °C, the vapor pressure of cyclohexane, a nonpolar hydrocarbon, is 66.9 torr and that of toluene, a hydrocarbon related tobenzene, is 21.1 torr. Calculate the expected vapor pressure of a mixture of cyclohexane and toluene that consists of 124 grams ofeach liquid.Ptotal=torr

Answered: At 20.0 °C, the vapor pressure of…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter12: Solutions

Section: Chapter Questions

Problem 12.86QE

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At 20.0 °C, the vapor pressure of cyclohexane, a nonpolar hydrocarbon, is 66.9 torr and that of toluene, a hydrocarbon related to
benzene, is 21.1 torr. Calculate the expected vapor pressure of a mixture of cyclohexane and toluene that consists of 124 grams of
each liquid.
Ptotal=
torr

Expert Solution

Step 1

Raoult's Law states that vapor pressure of a solution formed by volatile solute and volatile solvent is as follows

$P_{t o t a l} = (x_{1} P_{1}^{o}) + (x_{2} P_{2}^{o}) H e r e, x_{1} i s m o l e f r a c t i o n o f f i r s t c o m p o n e n t P_{1}^{o} i s t h e v a p o r p r e s s u r e f i r s t c o m p o n e n t i n p u r e s t a t e x_{2} i s m o l e f r a c t i o n o f s e c o n d c o m p o n e n t P_{2}^{o} i s t h e v a p o r p r e s s u r e s e c o n d c o m p o n e n t i n p u r e s t a t e$

Here vapor pressure of pure cyclohexane $(P_{1}^{o})$ is 66.9 torr and vapor pressure of pure toluene $(P_{2}^{o})$ is 21.1 torr.

Amount of each component is 124 grams.

We have to find total pressure of the solution

Molar mass of cyclohexane is 84.16 g/mol

Molar mass of toluene is 92.14 g/mol

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