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At 25 °C, the standard enthalpy of formation of HF (aq) is -319.9 kJ it is -285.8 kJ mol Part: 0/2 Part 1 of 2 Calculate the standard enthalpy of neutralization of HF (aq): HF (aq) + OH (aq) → F (aq) + H₂O (1) Be sure your answer has the correct number of significant digits. kJ mol X S , of OH (aq), it is - 229.6 mol' kJ mol of F (aq), it is -330.1 kJ mol and of H₂O (1),

At 25 °C, the standard enthalpy of formation of HF (aq) is -319.9 kJ it is -285.8 kJ mol Part: 0/2 Part 1 of 2 Calculate the standard enthalpy of neutralization of HF (aq): HF (aq) + OH (aq) → F (aq) + H₂O (1) Be sure your answer has the correct number of significant digits. kJ mol X S , of OH (aq), it is - 229.6 mol' kJ mol of F (aq), it is -330.1 kJ mol and of H₂O (1),

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 7QAP: Magnesium sulfate is often used in first-aid hot packs, giving off heat when dissolved in water. A...
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At 25 °C, the standard enthalpy of formation of HF (aq) is -319.9 kJ mol it is - 285.8 Part: 0/2 Part 1 of 2 Calculate the standard enthalpy of neutralization of HF (aq): HF (aq) + OH(aq) F (aq) + H₂O (1) Be sure your answer has the correct number of significant digits. kJ mol X kJ mol , of OH (aq), it is - 229.6 kJ , of F (aq), it is -330.1 mol' kJ mol and of H₂O (1),
Transcribed Image Text:At 25 °C, the standard enthalpy of formation of HF (aq) is -319.9 kJ mol it is - 285.8 Part: 0/2 Part 1 of 2 Calculate the standard enthalpy of neutralization of HF (aq): HF (aq) + OH(aq) F (aq) + H₂O (1) Be sure your answer has the correct number of significant digits. kJ mol X kJ mol , of OH (aq), it is - 229.6 kJ , of F (aq), it is -330.1 mol' kJ mol and of H₂O (1),
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