At a certain temperature, the K, for the decomposition of H₂S is 0.711. H₂S(g) = H₂(g) + S(g) Initially, only H₂S is present at a pressure of 0.171 atm in a closed container. What is the total pressure in the container at equilibrium? Macm Ptotal at
At a certain temperature, the K, for the decomposition of H₂S is 0.711. H₂S(g) = H₂(g) + S(g) Initially, only H₂S is present at a pressure of 0.171 atm in a closed container. What is the total pressure in the container at equilibrium? Macm Ptotal at
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter16: Thermodynamics
Section: Chapter Questions
Problem 50E: Consider the decomposition of CaCO3(s) into CaO(s) and Co2(g). What is the equilibrium partial...
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![Macmillan L
At a certain temperature, the Kp for the decomposition of H₂S is 0.711.
H₂S(g) = H₂(g) + S(g)
at equilibrium?
Initially, only H₂S is present at a pressure of 0.171 atm in a closed container. What is the total pressure in the container
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Ptotal
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Transcribed Image Text:Macmillan L
At a certain temperature, the Kp for the decomposition of H₂S is 0.711.
H₂S(g) = H₂(g) + S(g)
at equilibrium?
Initially, only H₂S is present at a pressure of 0.171 atm in a closed container. What is the total pressure in the container
$
Ptotal
101
4
=
At
R
D F
15
%
H
5
a
T
16
G
24
6
1 &
Y
7
H
18 4+
U
8
J
19
日 月 日
9
K
10
▶II
O
O
L
P
{
59°F A4 A
[
?
insert
}
]
← backspace
prt sc
"
pause
2:59 PM
10/1/2022
atm
delet
t
enter
↑
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