At a distance of 10 meters we have a radiation intensity of 0.1 mSv/h after passing through 48 mm of a shielding material (TVL of 16 mm). If an Ir-192 source is used
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- A monocrystalline silicon solar panel (active area: 1 m2) has an energy conversion efficiency of 20%. What is the power output when irradiance of 800 W/m2 is shining on the solar panel? Select one: a. 240 W. b. 400 W. c. 160 W. d. 80 W. e. 320 W.Draw a plot showing the variation of photoelectric current with collector plate potential for two different frequencies, v1 > v2, of incident radiation having the same intensity. In which case will the stopping potential be higher? Justify your answer.Q#01:a) Define Radiation and give at least 3 examples.b) Define Stefan-Boltzmann Law and emissivity. Is there any surface whose emissivity valueis greater than 1? If no, explain the reason.
- Calculate the percentage efficiency of a solar PV module whose length is 125 cm and width is 113 cm and produces 285 W maximum power when exposed to 1197 W/m2 solar irradiance? Answer:One of the given statement is true Kirchoff's law shows that emissivity is the same as transmissivity for blackbodies Incident radiation is the sum of the reflected and emitted radiation The sum of the absorptivity, transmissivity and reflectivity can be more than 1 for real bodies None of the given Radiosity is another form of the Stefan-Boltzmann lawThe rate of radiation heat transfer per unit area from a black surface is directly proportional to the fourth power of the absolute temperature of a surface. A. Boltzmann’s Law B. Kirchoff’s Law C. Newton’s Law of Coding D. Fourier’s Law
- The peak wavelength of radiation emitted by a black body at a temperature of 2000 K is 1.45 um. If the peak wavelength of emitted radiation changes to 2.90 um, then the temperature (in K) of the black body is A. 500 B. 1000 C. 4000 D. 800034.) A duct, consisted of four rectangular flat plates, are radiating with each otherand nothing else. Use the given data to find the radiosity and the rate of heattransfer for each surface. Data: Length = 1 m, depth, 2 m, height 0.5 m, T1 = 100C, T2 = 200 C, T3 = 300 C, T4 = 400 C, ε1 = 0.5, ε2 = 0.65, ε3 = 0.75, ε4 = 0.8. Thejoins are well insulated so that there is no heat transfer between the plates bythermal conduction.H4. Solar flux = 900 [w/m^2] h_air from glass cover = 25 [w/m^2-k] Emissivity_glass = 0.88 (nearly opaque to low frequency radiation Transmissivity of glass = 0.95 Alpha to incoming radiaiton = 0.9 T_ambient = 17 C Gap between plates = 25mm Bottom plate is insulated. Hr = radiation heat Hc = convective heat might need to use view factor FIND TEMPERATURE OF TOP SURFACE (the top is the glass) If anything is needed let me know i will try my best to update the question
- The peak wavelength of radiation emitted by a black body at a temperature of 2000 K is 1.45 micrometer. If the peak wavelength of emitted radiation changes to 2.90 micrometer, then the temperature (in K) of the black body is (A) 500 (B) 1000 (C) 4000 (D) 8000Radiant energy with an intensity of 800 W/m2 strikes a flat plate normally. The absorptivity is twice the transitivity and thrice the reflectivity. Determine the rate ofabsorption, transmission and reflection of energyHow does radiosity for a surface differ from the emitted energy? For what kind of surfaces are these two quantities identical?