At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.514 m. (a) Locate the image of a patient 11.8 m from the mirror. (Use the correct sign conventions.) .2515 Apply the mirror equation using the correct focal length and object distance to find the image distance. cm (from the mirror) (b) Indicate whether the image is upright or inverted. upright O inverted (c) Determine the magnification of the image. .02 Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Image Formation By Mirrors And Lenses
Section: Chapter Questions
Problem 18P
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Box answers for A and C, keep getting it wrong.

At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of
the mirror's radius of curvature is 0.514 m.
(a) Locate the image of a patient 11.8 m from the mirror. (Use the correct sign conventions.)
.2515
Apply the mirror equation using the correct focal length and object distance to find the image distance. cm (from the mirror)
(b) Indicate whether the image is upright or inverted.
upright
O inverted
(c) Determine the magnification of the image.
.02
Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of
your calculation.
Transcribed Image Text:At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.514 m. (a) Locate the image of a patient 11.8 m from the mirror. (Use the correct sign conventions.) .2515 Apply the mirror equation using the correct focal length and object distance to find the image distance. cm (from the mirror) (b) Indicate whether the image is upright or inverted. upright O inverted (c) Determine the magnification of the image. .02 Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation.
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