Question
Asked Dec 3, 2019
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At STP, 0.284 L of a gas weighs 0.401 g. Calculate the molar mass of the gas.

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Expert Answer

Step 1

Ideal gas equation is,

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PV nRT where P-Pressure T-Temperature R-Gasconstant V-Volume n-Number of moles

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Step 2

Given :

Volume of gas = 0.284

Mass of gas = 0.401 g

Temperature = 273 K

Pressure = 1 atm

R = 0.082.

Su...

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PV n= RT 1x0.284L =0.0127mol 0.0821x273 K Mass Molar mass= mole 0.401g -31.57 g/mol 0.0127mol -32.0 g/mol

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Science

Chemistry

Gas laws

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