At time t = 0, an electron with kinetic energy 16 keV moves through x = 0 in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 63.6 µT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinate x = 23 cm? (a) Number 8.4e+14 Units m/s^2 (b) Number i 6.7e+0 Units ст

At time t = 0, an electron with kinetic energy 16 keV moves through x = 0 in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 63.6 µT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinate x = 23 cm? (a) Number 8.4e+14 Units m/s^2 (b) Number i 6.7e+0 Units ст

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 22P

See similar textbooks

Similar questions

Assume the region to the right of a certain plane contains a uniform magnetic field of magnitude 1.00 mT and the field is zero in the region to the left of the plane as shown in Figure P22.71. An electron, originally traveling perpendicular to the boundary plane, passes into the region of the field. (a) Determine the time interval required for the electron to leave the field-filled region, noting that the electrons path is a semicircle. (b) Assuming the maximum depth of penetration into the field is 2.00 cm, find the kinetic energy of the electron.
Is B constant in magnitude for points that lie on a magnetic field line?
Does increasing the magnitude of a uniform magnetic field through which a charge is traveling necessarily mean increasing the magnetic force on the charge? Does changing the direction of the field necessarily mean a change in the force on the charge?
A mass spectrometer (Fig. 30.40, page 956) operates with a uniform magnetic field of 20.0 mT and an electric field of 4.00 103 V/m in the velocity selector. What is the radius of the semicircular path of a doubly ionized alpha particle (ma = 6.64 1027 kg)?
When the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0104 T. What is the radius of the loop?
A cosmic-ray electron moves at 7.5 × 106 m/sinches perpendicular to Earth’s magnetic field at an altitude queer the field strength is 1.0 × 105T. What is the radius of the circular path the electron follows?
A square loop whose sides are 6.0-cm long is made with copper wire of radius 1.0 mm. If a magnetic field perpendicular to the loop is changing at a rate of 5.0 mT/s, what is the current in the loop?
Calculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.
A proton travels with a speed of 3.00 106 m/s at an angle of 37.0 with the direction of a magnetic field of 0.300 T in the +y direction. What are (a) the magnitude of the magnetic force on the proton and (b) its acceleration?
Solenoid A has length L and N turns, solenoid B has length 2L and N turns, and solenoid C has length L/2 and 2N turns. If each solenoid carries the same current, rank the magnitudes of the magnetic fields in the centers of the solenoids from largest to smallest.
Show that the magnetic field at a distance r from the axis of two circular parallel plates, produced by placing charge Q(t) on the plates is Bind=02rdQ(t)dt
A wire 2.80 m in length carries a current of 5.00 A in a region where a uniform magnetic field has a magnitude of 0.390 T. Calculate the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is (a) 60.0, (b) 90.0, and (c) 120.