At time t = 13 s, the velocity of a particle moving in the x-y plane is v=0.05i + 2.54j m/s. By time t = 13.05 s, its velocity has become -0.12i+2.42j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: day = 0= i i m/s² O

At time t = 13 s, the velocity of a particle moving in the x-y plane is v=0.05i + 2.54j m/s. By time t = 13.05 s, its velocity has become -0.12i+2.42j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: day = 0= i i m/s² O